Solving Exponential Equations: Rewriting Bases and Using Logs

Solve.

e^-3n-9 = 92

• -2.5

• -2

• -4

• -4.5

Solve.

9(e^x) - 31 =23

• x = 1.79

• x = 4.21

• x = -3.5

• x = 1.27

To solve, 36 = 6^x, re-write 36 as what base and exponent?

• 3⁶

• 6³

• 6²

• 3¹²

Solve.

-10(9^-2x) = -97

• x= -1.16

• x= - 0.52

• x= - 0.49

• x= -1.14

To solve, 16^5x = 64^x+7, what would be the correct set-up?

There is more than one correct answer.

• 4^4(5x)=4^16(x+7)

• 8^2(5x)=8^8(x+7)

• 4^2(5x)=4^3(x+7)

• 2^4(5x)=2^6(x+7)

To solve, 3^4x = 81^x-4, re-write 81 as what base and exponent?

• 3²⁷

• 3⁴

• 4³

• 9²

Rewrite the exponential as a log.

e ^4x-3 = 9

• e^4x-3=9

• ln(12)=4x

• e⁹=4x-3

• ln(9)= 4x-3

To solve 8 = 2^5x+7, you would need to re-write 8 as what base?

• 8

• 4

• 2

• Cannot be determined

Tags

CCSS.8.EE.A.1

Solve.

2^x+10=8^x+1

• x=7/2

• x=7

• x=3

• x=-5

Solve.

10^x-3=10^8x-10

• x=2

• x=6

• x=1

• x=-4