Alg 1 Test Review Mod 1 Lessons 17-21

The linear equation below has two variables.

y= - 1/4 x + 1

Which shows the solutions to the equation when x = 4, x = 0, and x = –4.

• (–2, 4), (1, 0), (0. –4)

• (4, –2), (0, –1), (-4, 0)

• (2, –4), (–1, 0), (0, 4)

• (–4, 2), (0, 1), (4, 0)

Which of the following is a solution to the inequality graphed?

• (0, 0)

• (2, 5)

• (0, –3)

• (–1, 1)

Solve the literal equation for the given variable.

• 2A/h
• 2/(h)
• 2Ah
• Ah/2

Tags

CCSS.HSA.CED.A.4

S = 3F - 24  Solve for F

• F = (S + 24)/3
• F = S/3 + 24
• F = 3S + 24
• F = 3(S + 24)

Tags

CCSS.HSA.CED.A.4

Solve for y:
8x + 4y= 16

• y = -8x + 16
• y = 2x -4
• y = -2x + 4
• y = -8x + 12

Tags

CCSS.6.EE.C.9

Solve for t.
D= rt

• D/r = t
• Dr = t
• D/t = r
• Dt = r

Tags

CCSS.HSA.CED.A.4

• (2.5+h)f
• g=1
• f(5+h)/2
• (5f+h) / 2

Tags

CCSS.HSA.CED.A.4

ax + c = R
(solve for x) 

• ax = R + c
• ax = R - c
• x = a(R-c)
• x = ^(R-c)/_a 

Tags

CCSS.HSA.REI.B.3

What type of slope does the following graph have?

• Postive
• Negative
• Zero Slope
• Undefined

Tags

CCSS.8.EE.B.5

In the equation y=mx+b, what does the m represent?

• slope
• y-intercept
• linear
• point-slope

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3