Chemistry - Gas Laws Practice

The 36,000 L balloon section of a small hot air balloon is initially cool at 22°C. Later it is heated to an average temperature of 117°C. What will its new volume be?

What is the first step in solving this problem?

• Choosing the correct gas law equation for the problem.

• Plugging the numbers into one of the gas law equations.

• Using a calculator to calculate the answer.

• Identifying the numbers (and assigning them symbols / letters).

The 36,000 L balloon section of a small hot air balloon is initially cool at 22°C. Later it is heated to an average temperature of 117°C. What will its new volume be?

What symbol / letter corresponds to 36,000 L?

• The starting pressure (P₁)

• The starting volume (V₁)

• The starting temperature (T₁)

• The ending volume (V₂)

• The ending temperature (T₂)

Tags

NGSS.HS-PS3-4

The 36,000 L balloon section of a small hot air balloon is initially cool at 22°C. Later it is heated to an average temperature of 117°C. What will its new volume be?

What symbol / letter corresponds to 117°C?

• The starting pressure (P₁)

• The starting volume (V₁)

• The starting temperature (T₁)

• The ending volume (V₂)

• The ending temperature (T₂)

Tags

NGSS.HS-PS3-4

The 36,000 L balloon section of a small hot air balloon is initially cool at 22°C. Later it is heated to an average temperature of 117°C while the pressure stays at a constant 90 kPa. What will its new volume be?

Which equation should be used?

• Boyle's Law (P₁·V₁=P₂·V₂)

• Charles' Law (V₁/T₁ = V₂/T₂)

• Some other gas law equation.

The 36,000 L balloon section of a small hot air balloon is initially cool at 22°C. Later it is heated to an average temperature of 117°C. What will its new volume be?

What should we do to the temperature before plugging it into the equation?

• Convert it into degrees Fahrenheit (°F).

• Convert it into Kelvin (K).

• Nothing. It is fine in degrees Fahrenheit (°C).

• Change it into a pressure in kilopascals (kPa).

The 36,000 L balloon section of a small hot air balloon is initially cool at 22°C. Later it is heated to an average temperature of 117°C. What will its new volume be?

What are the temperatures in Kelvin?

• 22°C = 71.6K & 117°C = 243K

• 22°C = -5.6K & 117°C = 47.2K

• 22°C = 295K & 117°C = 390K

• 22°C = -251K & 117°C = -156K

Tags

NGSS.HS-PS1-5

The 36,000 L balloon section of a small hot air balloon is initially cool at 22°C. Later it is heated to an average temperature of 117°C. What will its new volume be?

Solve the problem.

• 122 L

• 10,980 L

• 47,600 L

• 3,240,000 L

• 10,620,000 L

Tags

NGSS.HS-PS3-4