To solve x + 12 𝑥 + 2 ≤ 2 \frac{x+12}{𝑥+2}≤2 x + 2 x + 1 2 ≤ 2 , first, we transform the given inequality into its general form which is...

x + 12 𝑥 + 2 − 2 ≤ 0 \frac{x+12}{𝑥+2}-2≤0 x + 2 x + 1 2 − 2 ≤ 0

x + 12 𝑥 + 2 + 2 ≤ 0 \frac{x+12}{𝑥+2}+2≤0 x + 2 x + 1 2 + 2 ≤ 0

2 ( x + 12 𝑥 + 2 ) ≤ 0 2\left(\frac{x+12}{𝑥+2}\right)≤0 2 ( x + 2 x + 1 2 ) ≤ 0

1 2 ( x + 12 𝑥 + 2 ) ≤ 0 \frac{1}{2}\left(\frac{x+12}{𝑥+2}\right)≤0 2 1 ( x + 2 x + 1 2 ) ≤ 0

Based from − x + 8 𝑥 + 2 ≤ 0 \frac{-x+8}{𝑥+2}≤0 x + 2 − x + 8 ≤ 0 , what are the critical values of the given rational inequality?

− 8 & − 2 -8\ \&\ -2 − 8 & − 2

solving rational equations

Authored by Hishsam sanuri

Mathematics

11th Grade

CCSS covered

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MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Solve for v

- 7/6

- 9/5

9/5

-3

Tags

CCSS.HSA.REI.A.2

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Solve for r

- 5, 4

- 5

5, 4

Tags

CCSS.HSA.REI.A.2

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Solve for x

1/3

-5.5

5.5

2.5

Tags

CCSS.HSA.REI.A.2

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Solve for x

-2

-4

Tags

CCSS.HSA.REI.A.2

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Solve and check for extraneous solutions

x=5

x= -5

No Solution

Tags

CCSS.HSA.REI.A.2

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Solve and check for extraneous solutions

x= - 3 &x= -8

x= -3 & -8 is extraneous

No Solution

x= -8 & -3 is extraneous

Tags

CCSS.HSA.REI.A.2

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Solve the equation for x.

Tags

CCSS.HSA.REI.A.2

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solving rational equations

Solve for v

Solve for r

Solve for x

Solve for x

Solve and check for extraneous solutions

Solve and check for extraneous solutions

Solve the equation for x.

Solve and check for extraneous solutions

Solve.

Solve.

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