Unit 10 Lesson 4

The axis of symmetry is a line that goes through the...

• y-intercept

• x-intercept

• vertex

• x-axis or y-axis

Keith determined the zeros of the function to be -6 and 5. What could be Keith's function?

• f(x) = (x + 6)(x - 5)

• f(x) = (x - 6)(x + 5)

• f(x) = (x + 6)(x + 5)

• f(x) = (x - 6)(x - 5)

Solve:
x² - 49 = 0

• x = -7, x = 7
• x = -7
• x = 7
• x = -7, x = 1

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 13x + 12 = 0

• x = -1, x = -12
• x = -1, x = -24
• x = -2, x = -6
• x = -2, x = -12

Tags

CCSS.HSA-REI.B.4B

Find the zeros.

• 0 and 4
• 0 and -4
• 0
• -4

Tags

CCSS.HSF-IF.C.7A

Determine the values of
a, b, and c for
the quadratic equation: 
4x² – 8x = 3

• a = 4, b = -8, c = 3
• a = 4, b =-8, c =-3
• a = 4, b = 8, c = 3
• a = 4, b = 8, c = -3

Tags

CCSS.HSA.REI.B.4

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Tags

CCSS.HSA-REI.B.4B

Find the zeros of this quadratic.

• b=4/5, b=3
• b=4, b=-3
• b=1/5, b=3
• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

Suzie solves the equation below:

x² + 4x - 12 = 2

(x - 2)(x + 6) = 2,

by setting x -2 = 0 and x + 6 = 0.

Her solutions are x = 2 and x = -6.

Is Suzie correct? Why or why not?

• Yes, she factored and solved correctly

• No, she factored incorrectly

• No, she didn't set the equation equal to zero first

• No, she has the wrong solutions, it should be

  x = -2 and x = 6

What is another word for the solutions to a quadratic?

• y-intercept
• Axis of Symmetry
• Parabola
• Roots

Tags

CCSS.HSF-IF.C.7A