1.1 CPU & VON NEUMANN ARCHITECTURE

1.1 CPU & VON NEUMANN ARCHITECTURE

8th - 10th Grade

10 Qs

quiz-placeholder

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1.1 CPU & VON NEUMANN ARCHITECTURE

1.1 CPU & VON NEUMANN ARCHITECTURE

Assessment

Quiz

Computers

8th - 10th Grade

Hard

Created by

Archie Holmes

Used 494+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main purpose of the CPU?

To Fetch, Decode and Execute Instructions (in MEMORY).

To perform calculations.

To render graphics on a screen.

To manage the computer system.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main feature of the von Neumann Computer architecture?

There is a single PRIMARY MEMORY for both data and instructions.

The model as a single CPU

The instructions are stored in PRIMARY MEMORY

Data is stored in SECONDARY STORAGE

3.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

What are the MAIN COMPONENTS of the CPU? (Tick all that are correct).

ALU

CU

Registers

Cache MEmory

BIOS

4.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Which of these are REGISTERS in the CPU? (Tick ALL that are correct)

Accumulator

ALU

Program Counter

Memory Address Register

Control Bus Register

5.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Tick all options that happen in the FETCH CYCLE?

PC is incremented

The Instruction at the MAR address is read from RAM

The PC value is copied to the MAR

The instruction in the IR is decoded

The value in the MDR is written to the address in the MAR.

6.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Tick all options that happen in the DECODE CYCLE?

PC is incremented

The Instruction at the MAR address is read from RAM

The PC value is copied to the MAR

The instruction in the IR is decoded by the CU

The value in the MDR is written to the address in the MAR.

7.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Tick all options that happen in the EXECUTE CYCLE?

IR is incremented

The data at the MAR address is read from RAM

The ALU performs any calculations required on the ACC

The instruction in the IR is decoded by the CU

The value in the MDR is written to the address in the MAR.

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