energi ikatan termokimia

energi ikatan termokimia

11th Grade

15 Qs

quiz-placeholder

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energi ikatan termokimia

energi ikatan termokimia

Assessment

Quiz

Chemistry

11th Grade

Hard

Created by

Kicky Wardani

Used 256+ times

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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

+94 kJ

+81 kJ

-81 kJ

-94 kJ

-208 kJ

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

1.173,5 kJ

735,5 kJ

391 kJ

245 kJ

130 kJ

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Diketahui
N2(g) + 3H2(g) --> 2NH3(g)        Δ\Delta  H= - 107 kJ/mol
jika energi ikatan :
N  \equiv   N : 941 kJ/mol
H – H : 436 kJ/mol
maka energi ikatan rata-rata N-H dalam NH3 adalah … .

393 kJ/mol

642 kJ/mol

782 kJ/mol

2249 kJ/mol

2346 kJ/mol

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Diketahui energi ikat:

H – I = 299 kJ/mol

H – H = 436 kJ/mol

I – I = 151 kJ/mol

maka kalor yang diperkukan untuk menguraikan 256 gram HI (Ar H = 1; I = 127) menjadi unsur-unsurnya adalah … .

5,5, kj

11,0 kj

22,0 kj

44,0 kj

88,0 kj

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Diketahui energi ikatan rata-rata untuk
C – C : 348 kJ/mol   C – Cl : 328 kJ/mol
C = C : 641 kJ/mol  H – Cl : 431 kJ/mol
C – H : 413 kJ/mol
Maka perubahan entalpi reaksi
H2C = CH2 + HCl  \rightarrow   H3C – CH2 – Cl   adalah … .

– 17 kJ

+ 17 kJ

– 44 kJ

+ 44 kJ

+ 47 kJ  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Dari data :

2 H2(g) + O2 (g) → 2 H2O(l) ∆H=-571 kJ

2 Ca(s) + O2 (g) → 2 CaO(s) ∆H = -1269 kJ

CaO(s) + H2O (l) → Ca(OH)2 (s) ∆H=-64 kJ

Harga ∆H0f kalsium hidroksida adalah ....

-984 kJ/mol

-1161 kJ/mol

-856 kJ/mol

-1904 kJ/mol

-1966 kJ/mol

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Padatan kalsium oksida direaksikan dengan air membentuk senyawa kalsium hidroksida berbentuk padatan. Dalam reaksi tersebut terjadi pelepasan kalor sebesar 64 kJ. Persamaan termokimia yang benar untuk reaksi tersebut adalah......

CaO(s) + H2O (l) → Ca(OH)2(s) ∆H=+64 kJ

CaO(s) + H2O (l) → Ca(OH)2(s) ∆H=-64 kJ

CaO(s) + H2O (l) → Ca(OH)2(aq) ∆H=-64 kJ

CaO(s) + H2O (l) → Ca(OH)2(aq) ∆H=+64 kJ

CaO(s) + 2 H2O (l) → Ca(OH)2(s) ∆H=-64 kJ

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