Latihan UTS Trigonometri

Latihan UTS Trigonometri

10th Grade

10 Qs

quiz-placeholder

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Latihan UTS Trigonometri

Latihan UTS Trigonometri

Assessment

Quiz

Mathematics

10th Grade

Hard

Created by

hendy cahya

Used 12+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Jika  tan A = 32\tan\ A\ =\ \frac{\sqrt{3}}{\sqrt{2}}  , maka nilai  sinA×cosA=\sin A\times\cos A=\cdot\cdot\cdot  

 65\frac{\sqrt{6}}{\sqrt{5}}  

 65\frac{\sqrt{6}}{5}  

 56\frac{5}{\sqrt{6}}  

 3+25\frac{\sqrt{3}+\sqrt{2}}{\sqrt{5}}  

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Nilai dari tan 2205 =...

1

3\sqrt{3}

133\frac{1}{3}\sqrt{3}

\infty

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 cos 1200=\cos\ -1200=\cdot\cdot\cdot  

 123-\frac{1}{2}\sqrt{3}  

 123\frac{1}{2}\sqrt{3}  

 12\frac{1}{2}  

 12-\frac{1}{2}  

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Jika sinA=1213\sin A=\frac{12}{13}  dan  cosB=35\cos B=\frac{3}{5}  , maka nilai dari  sinAcosB +cosAsinB =\sin A\cdot\cos B\ +\cos A\cdot\sin B\ =\cdot\cdot\cdot  

 6556\frac{65}{56}  

 6556-\frac{65}{56}  

 5665\frac{56}{65}  

 5665-\frac{56}{65}  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Jika π<A<32π\pi<A<\frac{3}{2}\pi  dan  sinA=aa+1\sin A=\frac{-\sqrt{a}}{\sqrt{a+1}}  maka nilai dari  tan2A + cos2A =\tan^2A\ +\ \cos^2A\ =\cdot\cdot\cdot  

 a2+a+1a+1\frac{a^2+a+1}{a+1}  

 a2+a1a+1\frac{a^2+a-1}{a+1}  

 a2a+1a1\frac{a^2-a+1}{a-1}  

 a2a1a+1\frac{a^2-a-1}{a+1}  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Aldo sedang bermain layang-layang di tanah lapang. Panjang benang layang-layang yang sudah diulur oleh Aldo adalah 100 m. Aldo memandang layang-layangnya dengan sudut elevasi 45°45\degree . Jika tinggi Aldo adalah  50250\sqrt{2}   cm, tentukan jarak layang-layang Aldo ke tanah!

 1002m100\sqrt{2}m  

 552m55\sqrt{2}m  

 50,52 m50,5\sqrt{2\ }m  

 50+502m50+50\sqrt{2}m  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Bentuk sederhana dari 1cos2X1+sinX1-\frac{\cos^2X}{1+\sin X}  adalah...

 sinX\sin X  

 cosX\cos X  

 tanX\tan X  

 cosecX\operatorname{cosec}X  

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