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三角関数の加法定理を覚えるTraining

Authored by Kenji Takei

Mathematics

11th - 12th Grade

Used 23+ times

三角関数の加法定理を覚えるTraining
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12 questions

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1.

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

正しいものを選べ
 sin(α+β)=\sin\left(\alpha+\beta\right)=  

 sinαcosβ+cosαsinβ\sin\alpha\cos\beta+\cos\alpha\sin\beta  

 sinαcosβcosαsinβ\sin\alpha\cos\beta-\cos\alpha\sin\beta  

 cosαcosβsinαsinβ\cos\alpha\cos\beta-\sin\alpha\sin\beta  

 cosαcosβ+sinαsinβ\cos\alpha\cos\beta+\sin\alpha\sin\beta  

2.

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

正しいものを選べ
 sin(αβ)=\sin\left(\alpha-\beta\right)=  

 sinαcosβ+cosαsinβ\sin\alpha\cos\beta+\cos\alpha\sin\beta  

 sinαcosβcosαsinβ\sin\alpha\cos\beta-\cos\alpha\sin\beta  

 cosαcosβsinαsinβ\cos\alpha\cos\beta-\sin\alpha\sin\beta  

 cosαcosβ+sinαsinβ\cos\alpha\cos\beta+\sin\alpha\sin\beta  

3.

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

正しいものを選べ
 cos(α+β)=\cos\left(\alpha+\beta\right)=  

 sinαcosβ+cosαsinβ\sin\alpha\cos\beta+\cos\alpha\sin\beta  

 sinαcosβcosαsinβ\sin\alpha\cos\beta-\cos\alpha\sin\beta  

 cosαcosβsinαsinβ\cos\alpha\cos\beta-\sin\alpha\sin\beta  

 cosαcosβ+sinαsinβ\cos\alpha\cos\beta+\sin\alpha\sin\beta  

4.

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

正しいものを選べ
 cos(αβ)=\cos\left(\alpha-\beta\right)=  

 sinαcosβ+cosαsinβ\sin\alpha\cos\beta+\cos\alpha\sin\beta  

 sinαcosβcosαsinβ\sin\alpha\cos\beta-\cos\alpha\sin\beta  

 cosαcosβsinαsinβ\cos\alpha\cos\beta-\sin\alpha\sin\beta  

 cosαcosβ+sinαsinβ\cos\alpha\cos\beta+\sin\alpha\sin\beta  

5.

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

正しいものを選べ
 tan(α+β)=\tan\left(\alpha+\beta\right)=  

 tanα+tanβ1tanαtanβ\frac{\tan\alpha+\tan\beta}{1-\tan\alpha\tan\beta}  

 tanαtanβ1+tanαtanβ\frac{\tan\alpha-\tan\beta}{1+\tan\alpha\tan\beta}  

 tanα+tanβ1+tanαtanβ\frac{\tan\alpha+\tan\beta}{1+\tan\alpha\tan\beta}  

 tanαtanβ1tanαtanβ\frac{\tan\alpha-\tan\beta}{1-\tan\alpha\tan\beta}  

6.

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

正しいものを選べ
 tan(αβ)=\tan\left(\alpha-\beta\right)=  

 tanα+tanβ1tanαtanβ\frac{\tan\alpha+\tan\beta}{1-\tan\alpha\tan\beta}  

 tanαtanβ1+tanαtanβ\frac{\tan\alpha-\tan\beta}{1+\tan\alpha\tan\beta}  

 tanα+tanβ1+tanαtanβ\frac{\tan\alpha+\tan\beta}{1+\tan\alpha\tan\beta}  

 tanαtanβ1tanαtanβ\frac{\tan\alpha-\tan\beta}{1-\tan\alpha\tan\beta}  

7.

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

正しいものを選べ
 sinαcosβ+cosαsinβ=\sin\alpha\cos\beta+\cos\alpha\sin\beta=  

 sin(α+β)\sin\left(\alpha+\beta\right)  

 sin(αβ)\sin\left(\alpha-\beta\right)  

 cos(α+β)\cos\left(\alpha+\beta\right)  

 cos(αβ)\cos\left(\alpha-\beta\right)  

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