Jumlah dan Selisih Sudut

Jumlah dan Selisih Sudut

11th Grade

10 Qs

quiz-placeholder

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Jumlah dan Selisih Sudut

Jumlah dan Selisih Sudut

Assessment

Quiz

Mathematics

11th Grade

Medium

Created by

Ayu Erika Puspasari

Used 194+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 sin(105°)=...\sin\left(105\degree\right)=...  

 \frac{1}{4}\sqrt{8}  

 12(2+6)\frac{1}{2}\left(\sqrt{2}+\sqrt{6}\right)  

 14(2+6)\frac{1}{4}\left(\sqrt{2}+\sqrt{6}\right)  

 14(26)\frac{1}{4}\left(\sqrt{2}-\sqrt{6}\right)  

 14(62)\frac{1}{4}\left(\sqrt{6}-\sqrt{2}\right)  

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 sin(15°)=...\sin\left(15\degree\right)=...  

 \frac{1}{4}\sqrt{8}  

 12(2+6)\frac{1}{2}\left(\sqrt{2}+\sqrt{6}\right)  

 14(2+6)\frac{1}{4}\left(\sqrt{2}+\sqrt{6}\right)  

 14(26)\frac{1}{4}\left(\sqrt{2}-\sqrt{6}\right)  

 14(62)\frac{1}{4}\left(\sqrt{6}-\sqrt{2}\right)  

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 cos(75°)=...\cos\left(75\degree\right)=...  

 \frac{1}{4}\sqrt{8}  

 12(2+6)\frac{1}{2}\left(\sqrt{2}+\sqrt{6}\right)  

 14(2+6)\frac{1}{4}\left(\sqrt{2}+\sqrt{6}\right)  

 14(26)\frac{1}{4}\left(\sqrt{2}-\sqrt{6}\right)  

 14(62)\frac{1}{4}\left(\sqrt{6}-\sqrt{2}\right)  

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 cos(15°)=...\cos\left(-15\degree\right)=...  

 \frac{1}{4}\sqrt{8}  

 12(2+6)\frac{1}{2}\left(\sqrt{2}+\sqrt{6}\right)  

 14(6+2)\frac{1}{4}\left(\sqrt{6}+\sqrt{2}\right)  

 14(26)\frac{1}{4}\left(\sqrt{2}-\sqrt{6}\right)  

 14(62)\frac{1}{4}\left(\sqrt{6}-\sqrt{2}\right)  

5.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

 cos85°cos55°+sin85°sin55°=...\cos85\degree\cos55\degree+\sin85\degree\sin55\degree=...  

0

1

 12\frac{1}{2}  

 122\frac{1}{2}\sqrt{2}  

 123\frac{1}{2}\sqrt{3}  

6.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

 sin75°cos15°cos75°sin15°=...\sin75\degree\cos15\degree-\cos75\degree\sin15\degree=...  

0

1

 12\frac{1}{2}  

 122\frac{1}{2}\sqrt{2}  

 123\frac{1}{2}\sqrt{3}  

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Diketahui sinAcosB=1565\sin A\cos B=\frac{15}{65}   dan  sin(A+B)=6365\sin\left(A+B\right)=\frac{63}{65} . Nilai dari  cosAsinB=...\cos A\sin B=...  

 4365\frac{43}{65}  

 4865\frac{48}{65}  

 7265\frac{72}{65}  

 8665\frac{86}{65}  

 9665\frac{96}{65}  

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