SUDUT RANGKAP TRIGONOMETRI

SUDUT RANGKAP TRIGONOMETRI

11th Grade

10 Qs

quiz-placeholder

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SUDUT RANGKAP TRIGONOMETRI

SUDUT RANGKAP TRIGONOMETRI

Assessment

Quiz

11th Grade

Hard

Created by

Ahmad Dulrohim

Used 660+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Diketahui  cosA=12\cos A=\frac{1}{2}  dengan A sudut lancip, nilai dari sin 2A = .....

 12-\frac{1}{2}  

 123-\frac{1}{2}\sqrt{3}  

  12\ \frac{1}{2}  

  123\ \frac{1}{2}\sqrt{3}  

 3\sqrt{3}  

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Diketahui  tanA= 13\tan A=\ \frac{1}{3}  dengan A sudut lancip, nilai dari sin 2A = ....

0

  25\ \frac{2}{5}  

  35\ \frac{3}{5}  

  45\ \frac{4}{5}  

1

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 tan6x\tan6x  equivalen dengan....

 2tan3x1tan3x\frac{2\tan3x}{1-\tan3x}  

  2tan3x1tan23x\ \frac{2\tan3x}{1-\tan^23x}  

 tan3x1tan23x\frac{\tan3x}{1-\tan^23x}  

  2tan3x1+tan23x\ \frac{2\tan3x}{1+\tan^23x}  

  3tan2x1tan22x\ \frac{3\tan2x}{1-\tan^22x}  

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 sin20o=....\sin20^o=....  

 2sin10ocos20o2\sin10^o\cos20^o  

 sin10ocos10o\sin10^o\cos10^o  

 2sin10ocos10o2\sin10^o\cos10^o  

 cos210osin210o\cos^210^o-\sin^210^o  

 12cos210o1-2\cos^210^o  

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 cos2 12A=....\cos^2\ \frac{1}{2}A=....  

  12+ 12cosA\ \frac{1}{2}+\ \frac{1}{2}\cos A  

  12+ 12cos2A\ \frac{1}{2}+\ \frac{1}{2}\cos2A  

  12+cos2A\ \frac{1}{2}+\cos2A  

  12 12sin2A\ \frac{1}{2}-\ \frac{1}{2}\sin2A  

  12 12cos2A\ \frac{1}{2}-\ \frac{1}{2}\cos2A  

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 sinA= 155\sin A=\ \frac{1}{5}\sqrt{5}  maka nilai dari cos 2A = .....

  15\ \frac{1}{5}  

  35\ \frac{3}{5}  

  45\ \frac{4}{5}  

  67\ \frac{6}{7}  

1

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Jika  180oα270o180^o\le\alpha\le270^o  dan  tanα=t\tan\alpha=t  maka  sin2α=...\sin2\alpha=...  

  1t\ \frac{1}{t}  

  1+t1t\ \frac{1+t}{1-t}  

  11+t2\ \frac{1}{1+t^2}  

  2t1t2\ \frac{2t}{1-t^2}  

  2t1+t2\ \frac{2t}{1+t^2}  

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