Chapter 2 Review

Chapter 2 Review

9th - 10th Grade

27 Qs

quiz-placeholder

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Chapter 2 Review

Chapter 2 Review

Assessment

Quiz

Mathematics

9th - 10th Grade

Medium

CCSS
HSG.CO.C.9, HSA.REI.A.1, HSG.CO.A.1

+9

Standards-aligned

Created by

Lindy (WHS)

Used 52+ times

FREE Resource

27 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which reason justifies the statement below?


CD + DE = CE and DE = XY, then CD + XY = CE

Segment Addition Postulate

Substitution Property of =

Symmetric Property of =

Transitive Property of =

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which reason justifies the statement below?


If MN = PQ, then MN ≅ PQ.

Definition of Congruent Segments

Definition of Midpoint

Reflexive Property

Symmeric Property

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which reason justifies the statement below?


BC + CD = EF and EF = GH + JK, then BC + CD = GH + JK

Segment Addition Postulate

Addition Property

Subtraction Property

Transitive Property

Tags

CCSS.HSA.REI.A.1

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which reason justifies the statement below?


AB + CD = CD + EF, then AB = EF.

Addition Property

Subtraction Property

Reflexive Property

Substitution Property

Tags

CCSS.HSA.REI.A.1

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Which reason justifies the statement below?


If AB ⊥ MN, then <MNB is a right angle.

Complement Thereom

Definition of Complementary Angles

Definition of Right Anlge

Definition of Perpendicular

Tags

CCSS.HSG.CO.A.1

CCSS.HSG.CO.C.9

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which reason justifies the statement below?


If <T and <U are complementary, then m<T + m<U = 90.

Complements Theorem

Definition of Right Angles

Definition of Complementary Angles

Congruent Complements Theorem

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Which reason justifies the statement below?

 4 2\angle4\ \cong\angle2  

Definition of Congruent Angles

Vertical Angles Theorem

Angle Addition Postulate

Supplements Theorem

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