Solving One Step Adding and Subtracting Equations (HW)

x + 2 = 10

• 12
• 10
• 2
• 8

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.7

x - 8 = 5

• 13
• -3
• -8
• -13

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

-2 + x = 15

• 15
• 17
• -2
• 13

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

x - 12 = 24

• -12
• 36
• 12
• 0

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

14 = x - 5

• -19
• 5
• 19
• 9

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.5

CCSS.6.EE.B.7

x+8=10

• x=2
• x=5
• x=0
• x=1

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

What is the inverse of subtraction?

• Dividing
• Multiplying
• Adding
• Subtracting

Tags

CCSS.2.NBT.B.5

CCSS.2.NBT.B.7

CCSS.2.NBT.B.9

Which procedure could be used to find the value for x that makes the statement true?
 
x + 22 = 64

• Multiply both sides of the equation by 22
• Divide both sides of the equation by 22
• Add 22 to both sides of the equation
• Subtract 22 from both sides of the equation

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.7

Which procedure could be used to find the value for x that makes the statement true?
x - 12 = 34

• Subtract 12 from both sides of the equation
• Add 12 to both sides of the equation
• Multiply both sides of the equation by 12
• Divide both sides of the equation by 12

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.7

-16+ x= -15

1st Step:

• Add 15

• Subtract 15

• Add 16

• Subtract 16

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7