2 2019 − 2 2017 − 2 2015 2 2019 − 2 2015 = . . . . \frac{\sqrt{2^{2019}}-\sqrt{2^{2017}}-\sqrt{2^{2015}}}{\sqrt{2^{2019}}-\sqrt{2^{2015}}}=\ .... 2 2 0 1 9 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2 2 0 1 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 2 2 0 1 9 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2 2 0 1 7 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2 2 0 1 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> = . . . .

− 2017 -\sqrt{2017} − 2 0 1 7 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 2 x 4 + 1 4 x 6 + 1 6 x 8 + . . . + 1 2016 x 2018 + 1 2018 x 2020 = . . . . \frac{1}{2x4}+\frac{1}{4x6}+\frac{1}{6x8}+...+\frac{1}{2016x2018}+\frac{1}{2018x2020}=.... 2 x 4 1 + 4 x 6 1 + 6 x 8 1 + . . . + 2 0 1 6 x 2 0 1 8 1 + 2 0 1 8 x 2 0 2 0 1 = . . . .

1010 4040 \frac{1010}{4040} 4 0 4 0 1 0 1 0

1005 4024 \frac{1005}{4024} 4 0 2 4 1 0 0 5

2010 4040 \frac{2010}{4040} 4 0 4 0 2 0 1 0

2010 4024 \frac{2010}{4024} 4 0 2 4 2 0 1 0

olimpiade matematika smp Kuis

15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Jika
A+B=20,
B+C=26,
C+D=28,
D+A=10
Maka A+B+C+D =.....

84

42

24

28

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.CED.A.3

CCSS.HSA.REI.C.6

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

N= bilangan asli 3 digit yang satuanya bukan 0.
M= bilangan asli 3 digit yang diperoleh dengan menukar satuan dan ratusan dari N
M+N = 908. Jumlah digit digit M adalah

12

13

14

15

18

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.CED.A.2

CCSS.HSA.REI.B.3

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Sisa dari $2^{2019}\div3$ adalah ....

-1

0

1

2

3

Tags

CCSS.HSA.APR.B.2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$Angka\ satuan\ dari\ \ 3^{2019\ }\ adalah$

0

1

3

7

9

Tags

CCSS.HSA.SSE.A.1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Hasil dari $\sqrt{5050^2-4950^2}$ adalah ....

10

100

1000

10000

100000

Tags

CCSS.HSA.REI.A.2

CCSS.HSN.RN.A.2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Jika a-b=2 dan ab=1, maka nilai dari
$a^2+b^2$ adalah ....

0

1

2

4

6

Tags

CCSS.HSA.SSE.B.3

CCSS.HSA.REI.B.4

CCSS.HSA.REI.C.7

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{\sqrt{2^{2019}}-\sqrt{2^{2017}}-\sqrt{2^{2015}}}{\sqrt{2^{2019}}-\sqrt{2^{2015}}}=\ ....$

1

$\frac{1}{3}$

$-\sqrt{2017}$

2

$\frac{1}{2}$

Tags

CCSS.HSA.SSE.B.3

CCSS.HSA.REI.A.2

CCSS.HSA.SSE.A.2

CCSS.HSN.RN.A.2

9.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Jika $3^n$ adalah faktor dari $18^{10}$ , maka bilangan bulat terbesar n yamh mungkin adalah ....

10

15

18

20

25

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olimpiade matematika smp

Jika
A+B=20,
B+C=26,
C+D=28,
D+A=10
Maka A+B+C+D =.....

N= bilangan asli 3 digit yang satuanya bukan 0.
M= bilangan asli 3 digit yang diperoleh dengan menukar satuan dan ratusan dari N
M+N = 908. Jumlah digit digit M adalah

Sisa dari $2^{2019}\div3$ adalah ....

$Angka\ satuan\ dari\ \ 3^{2019\ }\ adalah$

Hasil dari $\sqrt{5050^2-4950^2}$ adalah ....

Jika a-b=2 dan ab=1, maka nilai dari
$a^2+b^2$ adalah ....

$\frac{\sqrt{2^{2019}}-\sqrt{2^{2017}}-\sqrt{2^{2015}}}{\sqrt{2^{2019}}-\sqrt{2^{2015}}}=\ ....$

2, 3, 5, 8, 12, 17, ...
Suku ke 200 pada barisan di atas adalah ....

Jika $3^n$ adalah faktor dari $18^{10}$ , maka bilangan bulat terbesar n yamh mungkin adalah ....

Jika a, b, 15, c, dan d membentuk barisan aritmatika, maka a+b+c+d = ....

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Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

olimpiade matematika smp

Jika A+B=20, B+C=26, C+D=28, D+A=10 Maka A+B+C+D =.....

N= bilangan asli 3 digit yang satuanya bukan 0.M= bilangan asli 3 digit yang diperoleh dengan menukar satuan dan ratusan dari NM+N = 908. Jumlah digit digit M adalah

Sisa dari 22019÷32^{2019}\div322019÷3 adalah ....

Angka satuan dari 32019 adalahAngka\ satuan\ dari\ \ 3^{2019\ }\ adalahAngka satuan dari 32019 adalah

Hasil dari 50502−49502\sqrt{5050^2-4950^2}50502−49502​ adalah ....

Jika a-b=2 dan ab=1, maka nilai dari a2+b2a^2+b^2a2+b2 adalah ....

22019−22017−2201522019−22015= ....\frac{\sqrt{2^{2019}}-\sqrt{2^{2017}}-\sqrt{2^{2015}}}{\sqrt{2^{2019}}-\sqrt{2^{2015}}}=\ ....22019​−22015​22019​−22017​−22015​​= ....

2, 3, 5, 8, 12, 17, ...Suku ke 200 pada barisan di atas adalah ....

Jika 3n3^n3n adalah faktor dari 181018^{10}1810 , maka bilangan bulat terbesar n yamh mungkin adalah ....

Jika a, b, 15, c, dan d membentuk barisan aritmatika, maka a+b+c+d = ....

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Jika
A+B=20,
B+C=26,
C+D=28,
D+A=10
Maka A+B+C+D =.....

N= bilangan asli 3 digit yang satuanya bukan 0.
M= bilangan asli 3 digit yang diperoleh dengan menukar satuan dan ratusan dari N
M+N = 908. Jumlah digit digit M adalah

Sisa dari $2^{2019}\div3$ adalah ....

$Angka\ satuan\ dari\ \ 3^{2019\ }\ adalah$

Hasil dari $\sqrt{5050^2-4950^2}$ adalah ....

Jika a-b=2 dan ab=1, maka nilai dari
$a^2+b^2$ adalah ....

$\frac{\sqrt{2^{2019}}-\sqrt{2^{2017}}-\sqrt{2^{2015}}}{\sqrt{2^{2019}}-\sqrt{2^{2015}}}=\ ....$

2, 3, 5, 8, 12, 17, ...
Suku ke 200 pada barisan di atas adalah ....

Jika $3^n$ adalah faktor dari $18^{10}$ , maka bilangan bulat terbesar n yamh mungkin adalah ....