One-step Equations Classwork

y/3=12. What is being done to Y and what do you do to isolate the variable?

• Y is being divided by 3, so you need to divide both sides by 3.

• 3 is being added to Y, so you need to subtract 3 from both sides.

• Y is being divided by 3, so you need to multiply both sides by 3.

• Y is being divided by 3, so you need to add 3 to both sides.

Tags

CCSS.6.EE.B.7

To solve the equation:

4p = 16

what needs to be done to both sides to isolate the variable?

• Add 4

• Subtract 4

• Multiply by 4

• Divide by 4

Tags

CCSS.6.EE.B.7

What do you need to do to both sides to isolate the variable?

• Add 5

• Subtract 5

• Multiply by 5

• Divide by 5.

Tags

CCSS.6.EE.B.7

When solving the equation 3x = 27, what should you do to both sides to isolate the variable?

• Add 3

• Subtract 3

• Multiply by 3

• Divide by 3.

Tags

CCSS.HSA.REI.A.1

What is the correct step to solve for the variable?
15 = m - 5

• add 15 to both sides
• add 5 to both sides
• subtract 15 from both sides
• subtract 5 from both sides

Tags

CCSS.6.EE.B.7

How would you solve this equation: 9x=153?

• add 9 to both sides

• subtract 9 from both sides

• multiply 9 to both sides

• divide 9 from both sides

Tags

CCSS.6.EE.B.7

To solve the equation:

-5x = 25

the first step is:

• Add 5

• Subtract 5

• Multiply -5

• Divide -5

Tags

CCSS.6.EE.B.7

-16+ x= -15

1st Step:

• Add 15

• Subtract 15

• Add 16

• Subtract 16

Tags

CCSS.6.EE.B.7

-3x=12

Solve by doing what to both sides?

• Add 3

• Subtract 3

• Multiply by -3

• Divide by -3

Tags

CCSS.6.EE.B.7

Solve the equation: 
x + 7 = 12

• x = 5
• x = 19
• x = -5
• x = 84

Tags

CCSS.6.EE.B.7