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Persamaan Lingkaran

Authored by Tya Wahyu Tya Wahyu

Mathematics

11th Grade

CCSS covered

Used 200+ times

Persamaan Lingkaran
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16 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Persamaan lingkaran yang berpusat di (0,0) dan berjari-jari 2 3\sqrt{3}  

 x2+y2=12x^2+y^2=12  

 x2+y2=10x^2+y^2=10  

 x2+y2=8x^2+y^2=8  

 x2+y2=6x^2+y^2=6  

 x2+y2=4x^2+y^2=4  

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Persamaan lingkaran berpusat di (-2,3) berjari-jari 4 adalah ....

(x2)2+(y+3)2=4\left(x-2\right)^2+\left(y+3\right)^2=4

(x+2)2+(y3)2=4\left(x+2\right)^2+\left(y-3\right)^2=4

(x2)2+(y+3)2=16\left(x-2\right)^2+\left(y+3\right)^2=16

(x+2)2+(y3)2=16\left(x+2\right)^2+\left(y-3\right)^2=16

(x+2)2+(y3)2=36\left(x+2\right)^2+\left(y-3\right)^2=36

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Pusat dan jari-jari lingkaran yang persamaannya  (x+6)2+(y5)2=64\left(x+6\right)^2+\left(y-5\right)^2=64  adalah ....

Pusat (-5,6) dan jari-jari 8

Pusat (6,-5) dan jari-jari 64

Pusat (6,-5) dan jari-jari 8

Pusat (-6,5) dan jari-jari 64

Pusat (-6,5) dan jari-jari 8

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt


Soal UN 2002
Diketahui titik  (a,b)\left(a,b\right)  adalah titik pusat lingkaran  x2+y22x+4y+1=0x^2+y^2-2x+4y+1=0 . Maka nilai  2a+b2a+b  = ....

 2-2  

 1-1  

0

2

3

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Soal MAT IPA SBMPTN 2013
Persamaan lingkaran dengan pusat  (1,1)\left(-1,1\right)  dan menyinggung garis  3x4y+12=03x-4y+12=0  adalah....

 x2+y2+2x2y+1=0x^2+y^2+2x-2y+1=0  

 x2+y2+2x2y7=0x^2+y^2+2x-2y-7=0  

 4x2+4y2+8x8y17=04x^2+4y^2+8x-8y-17=0  

 x2+y2+2x2y2=0x^2+y^2+2x-2y-2=0  

 4x2+4y2+8x8y1=04x^2+4y^2+8x-8y-1=0  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt


Soal UN 2013
Persamaan lingkaran yang berpusat di  (1,3)\left(-1,3\right)  dan berdiameter  40\sqrt{40}  adalah....

 x2+y26x2y=0x^2+y^2-6x-2y=0  

 x2+y2+2x+6y=0x^2+y^2+2x+6y=0  

 x2+y22x2y=0x^2+y^2-2x-2y=0  

 x2+y2+2x6y=0x^2+y^2+2x-6y=0  

 x2+y22x6y=0x^2+y^2-2x-6y=0  

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Persamaan lingkaran yang berpusat di titik  (3, 4)\left(3,\ 4\right)   dan melalui titik  (3,2)\left(3,-2\right)   adalah....

 x2y26x8y11=0x^2-y^2-6x-8y-11=0  

 x2+y26x8y11=0x^2+y^2-6x-8y-11=0  

 x2+y26x8y+25=0x^2+y^2-6x-8y+25=0  

 x2y23x4y11=0x^2-y^2-3x-4y-11=0  

 x2y24x5y10=0x^2-y^2-4x-5y-10=0  

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