Electric Potential and Capacitance - Quick revision

The expression for Electric potential due to a point charge at a distance 'r' from it is____________

• $\frac{1}{4\pi\epsilon\ _{0\ }}\ \frac{q^{2\ }}{r}$

• $\frac{1}{4\pi\epsilon\ _{0\ }}\ \frac{q}{r}$

• $\frac{1}{4\pi\epsilon\ _{0\ }}\ \frac{q^{2\ }}{r^2}$

• $\frac{1}{4\pi\epsilon\ _{0\ }}\ \frac{q\ }{r^2}$

Tags

NGSS.HS-PS2-4

Electric potential at a point due to a dipole is

• $\frac{1}{4πε_o}\ \frac{p⃗.r⃗}{r^3}$

• $\frac{1}{4πε_o}\ \frac{p⃗.r⃗}{r^2}$

• $\frac{1}{4πε_o}\ \frac{p⃗.r⃗}{r}$

• $\frac{1}{4πε_o}\ p⃗.r⃗$

The relation between electric field and electric potential is

• $E=dV.dr$

• $V=dE.dr$

• $V=-\frac{dE}{dr}$

• $E=-\frac{dV}{dr}$

Electric potential energy of an electric dipole in a uniform electric field is given by

• 
  

  $U=\overrightarrow{p\ }\times\overrightarrow{E}$
  

• $U=\overrightarrow{E}\times\overrightarrow{p}$

• $U=-\overrightarrow{p\ }.\overrightarrow{E}$

• $U=-\frac{\left(\overrightarrow{p\ }.\overrightarrow{\ E\ }\right)}{\epsilon_o}$

Tags

NGSS.HS-PS2-4

NGSS.HS-PS3-5

The magnitude of  polarisation vector is given by

• 
  

   $P=\chi_{o\ }E$  
  

•  $P=\chi_{o\ }E^{2\ }$  

•  $P=\chi_{o\ }^2E$  

•  $P=\frac{\chi_{o\ }}{E}$  

The correct relationship between Capacitance (C), charge (Q) and potential (V) is

• C=QV

• Q=CV

• V=QC

• C=V/Q

The correct expression for the capacitance of a parallel plate capacitor is

• 
  

  $C=\frac{\epsilon_od}{A}$
  

• $C=\frac{\epsilon_oV}{Ad}$

• $C=\frac{\epsilon_oA}{d}$

• $C=\frac{\epsilon_o}{Ad}$

The correct expression for the capacitance of a parallel plate capacitor is filled with a dielectric of dielectric constant  $\kappa$  

•  $C=\kappa\frac{\epsilon_od}{A}$  

•  $C=\kappa\frac{\epsilon_oV}{Ad}$ 

•  $C=\kappa\frac{\epsilon_o}{Ad}$ 

•  $C=\kappa\frac{\epsilon_oA}{d}$ 

 The equivalent capacitance of three capacitors with capacitance  $C_1,\ C_2\ and\ C_3$  connected in series is 

•  $C=C_1+C_2+C_3$  

•  $\frac{1}{C}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}$  

•  $C=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}$  

•  $\frac{1}{C}=\frac{1}{C_1}\times\frac{1}{C_2}\times\frac{1}{C_3}$  

 The equivalent capacitance of three capacitors with capacitance  $C_1,\ C_2\ and\ C_3$  connected in parallel is 

•  $C=C_1+C_2+C_3$  

•  $\frac{1}{C}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}$  

•  $C=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}$  

•  $C=C_1C_2C_3$