FLSM and VLSM subnetting

Subnet mask from 10.10.10.0/25 is ?

• 255.255.0.0

• 255.255.255.128

• 255.255.255.127

• 255.255.128.0

Answer explanation

The subnet mask for 10.10.10.0/25 indicates that the first 25 bits are for the network. This corresponds to a subnet mask of 255.255.255.128, which allows for 128 IP addresses in the subnet.

What's the different beetwen ip private and ip public ?

• ip private is a ip just we use in the public network

• ip private is a ip that we use in the private network

• ip private is the same as ip public

• All answer is wrong

Answer explanation

IP private addresses are used within private networks, allowing devices to communicate internally without being exposed to the public internet. In contrast, IP public addresses are used for communication over the internet. Thus, the correct choice is that IP private is used in private networks.

Subnet of IP 172.16.10.10/16

• 255.255.0.0

• 255.255.255.0

• 255.0.0.0

• 255.128.255.255

Answer explanation

The subnet mask for the IP address 172.16.10.10 with a /16 prefix is 255.255.0.0. This indicates that the first 16 bits are used for the network part, allowing for a large number of hosts.

Broadcast from ip 192.168.10.0/29 is ?

• 192.168.10.127

• 192.168.127.255

• 192.168.255.255

• 192.168.10.7

Answer explanation

The subnet 192.168.10.0/29 has 8 IP addresses (0-7). The broadcast address is the last address in the range, which is 192.168.10.7. Therefore, the correct answer is 192.168.10.7.

Subnet of ip 10.10.10.0/9 ?

• 255.128.0.0

• 255.255.0.0

• 255.248.0.0

• 255.255.255.128

Answer explanation

The subnet mask for 10.10.10.0/9 indicates that the first 9 bits are for the network. This corresponds to a subnet mask of 255.128.0.0, which is the correct choice among the options provided.

Which of the following is the valid host range for the IP address 192.168.168.188 255.255.255.192 ?

• 192.168.168.129–190

• 192.168.168.129–191

• 192.168.168.128–190

• 192.168.168.128–192

Answer explanation

The subnet mask 255.255.255.192 indicates a /26 subnet, allowing for 64 IP addresses. The valid host range for the subnet containing 192.168.168.188 is 192.168.168.129 to 192.168.168.190, making this the correct choice.

What is the subnet address of the IP address 192.168.100.30 255.255.255.248?

• 192.168.100.32

• 192.168.100.24

• 192.168.100.0

• 192.168.100.16

Answer explanation

To find the subnet address, apply the subnet mask 255.255.255.248 (or /29) to the IP address 192.168.100.30. The subnet range is 192.168.100.24 to 192.168.100.31, making 192.168.100.24 the subnet address.

What is the valid host range the IP address 172.16.10.22 255.255.255.240 is a part of?

• 172.16.10.20 through 172.16.10.22

• 172.16.10.1 through 172.16.10.255

• 172.16.10.16 through 172.16.10.23

• D. 172.16.10.17 through 172.16.10.31

• 172.16.10.17 through 172.16.10.30

Answer explanation

The subnet mask 255.255.255.240 indicates a /28 subnet, which provides 16 IP addresses. The valid host range for 172.16.10.22 falls between 172.16.10.17 and 172.16.10.30, making this the correct choice.

What is the broadcast address of the subnet address 10.254.255.19 255.255.255.248?

• 10.254.255.23

• 10.254.255.24

• 10.254.255.255

• 10.255.255.255

Answer explanation

The subnet mask 255.255.255.248 indicates a /29 subnet, which has 8 IP addresses. The range is from 10.254.255.16 to 10.254.255.23. The broadcast address is the last address in this range, which is 10.254.255.23.

What is the broadcast address of the subnet address 172.16.99.99 255.255.192.0?

• 172.16.99.255

• 172.16.127.255

• 172.16.255.255

• 172.16.64.127

Answer explanation

To find the broadcast address, determine the subnet range. The subnet mask 255.255.192.0 corresponds to a /18 prefix, which means the last 14 bits are for hosts. The broadcast address for 172.16.99.99 is 172.16.127.255.