Algebra 2 S1 Exam Review

Solve the equation:
3(x - 1) = 2x + 9

• x = 12
• no solution
• x = 10
• x = 6

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

Solve the equation:
3x - x + 2 = 4(2x - 1)

• infinite solutions
• x = 1
• x = -1
• no solution

Tags

CCSS.8.EE.C.7A

Describe the solution set:
2(x + 5) = 2x + 5

• one solution
• no solution
• infinitely many solutions
• two solutions

Tags

CCSS.8.EE.C.7A

Solve the equation:
4 - 6x - 2= -2(3x-1)

• no solution
• infinitely many solutions
• x = ⅓
• x = 4

Tags

CCSS.8.EE.C.7A

Solve for x:

• x = yb - v
• x = by - v
• x = by + v

Tags

CCSS.HSA.REI.B.3

pV = nRT

solve for R

• $R=\frac{pV}{nT}$

• $R=\frac{p}{n}+\frac{V}{T}$

• R= pV - nT

• $R=\frac{pV-n}{T}$

Solve:

d = rt , for t

• $\frac{d}{r}=t$

• $\frac{r}{d}=t$

• d + r = t

• d - r = t

-3 − 6(4x + 6) > -111

• x > 3
• x < 3
• x < -3
• x > -3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

-138 ≥ -6(6b − 7)

• b ≤ 5
• b ≤ -5
• b ≥ 5
• b ≥ -5

Tags

CCSS.7.EE.B.4B

solve 5(6 + 3r) + 7 ≥ 127

• r ≤ 6

• r ≥ 6

• r ≤ -6

• r ≥ -6