Search Header Logo

Unit 4 Polynomials Test Review

Authored by Rachel Nolan

Mathematics

10th - 12th Grade

CCSS covered

Used 29+ times

Unit 4 Polynomials Test Review
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Simplify: (8x3)(7x4y3)\left(8x^3\right)\left(-7x^4y^3\right)  

 8x37x4y3\frac{8x^3}{7x^4y^3}  

 x7y3x^7y^3  

 56x7y3-56x^7y^3  

 87xy3\frac{8}{7xy^3}  

Tags

CCSS.HSA.APR.A.1

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Simplify. (2a3b2)5\left(\frac{2a^3}{b^{-2}}\right)^5  

 32a8b3\frac{32a^8}{b^3}  

 10a15b1010a^{15}b^{10}  

 10a15b10\frac{10a^{15}}{b^{10}}  

 32a15b1032a^{15}b^{10}  

Tags

CCSS.HSA.APR.A.1

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Simplify: (3x2 + 4x - 2) - (5x + 7)

3x2 - x - 9

2x2 - 9

3x2 + 9x - 5

3x2 - x + 5

Tags

CCSS.HSA.APR.A.1

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Simplify: (5x+2)(x2-3x+6)

5x3 - 17x2 +24x +12

5x3 + 17x2 - 24x +12

5x3 - 13x2 + 24x +12

5x3 +13x2 - 24x - 12

Tags

CCSS.HSA.APR.A.1

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Divide: (2x3 + 5x2 + 9) ÷ (x + 3)

2x2 - x + 3

2x3 - x2 + 3x

2x2 + 11x + 33 + 108/x+3

2x2 - 5x + 12

Tags

CCSS.HSA.APR.D.6

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

When setting up this synthetic division, what polynomial is being divided?

2x4 + 3x2 - x + 2
2x4 + 3x3 - x2 + 2
2x4 - 3x2 + x - 2
cannot be determined

Tags

CCSS.HSA.APR.D.6

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

If (x + 3) divides a polynomial function evenly, then which of these is known to be a zero of the polynomial?

x = -3
x = 3
x = 0
cannot be determined

Tags

CCSS.HSA.APR.B.2

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?