5.3.5 Parabolas Review

5.3.5 Parabolas Review

9th - 12th Grade

12 Qs

quiz-placeholder

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5.3.5 Parabolas Review

5.3.5 Parabolas Review

Assessment

Quiz

Mathematics

9th - 12th Grade

Hard

Created by

Kyleigh O'Boyle

Used 21+ times

FREE Resource

12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

Look at the graph of the parabola shown. Select the choice that states a possible focus and directrix for the graph.

Focus (-4, 4)

Directrix x=8

Focus (-4, 4)

Directrix y=8

Focus (4, -4)

Directrix x=8

Focus (4, -4)

Directrix y=8

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the vertex of the parabola represented by the following equation?  x=16(y4)28x=\frac{1}{6}\left(y-4\right)^2-8  

(-4, -8)

(4, -8)

(-8, 4)

(-8, -4)

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the focus of the parabola represented by the following equation?  y=116(x+4)2+2y=-\frac{1}{16}\left(x+4\right)^2+2  

(0, 2)

(0, -2)

(-4, -2)

(-4, 2)

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the directrix of the parabola represented by the following equation?  y=116(x+4)2+2y=-\frac{1}{16}\left(x+4\right)^2+2  

x=-6

y=-6

x=6

y=6

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Select the equation that represents a parabola in vertex form with vertex (3, -2) and directrix x=-6

x=136(y+2)2+3x=\frac{1}{36}\left(y+2\right)^2+3

y=136(x3)22y=\frac{1}{36}\left(x-3\right)^2-2

x=136(y+2)2+3x=-\frac{1}{36}\left(y+2\right)^2+3

y=136(x3)22y=-\frac{1}{36}\left(x-3\right)^2-2

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Select the equation that represents the parabola graphed on the coordinate plane.

x=14(y+2)24x=-\frac{1}{4}\left(y+2\right)^2-4

y=14(x4)2+2y=-\frac{1}{4}\left(x-4\right)^2+2

x=14(y2)2+4x=-\frac{1}{4}\left(y-2\right)^2+4

y=14(x+4)22y=-\frac{1}{4}\left(x+4\right)^2-2

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The cross section of a satellite dish is a parabola. Suppose a satellite dish receiver is located at the focus of the cross section, 10 feet in front of the vertex.

Assume the vertex is at the origin and that the parabola is concave left. Write an equation that represents the cross section of a satellite dish.

x=140y2x=\frac{1}{40}y^2

y=140x2y=\frac{1}{40}x^2

y=140x2y=-\frac{1}{40}x^2

x=140y2x=-\frac{1}{40}y^2

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