Đạo hàm

Đạo hàm

11th Grade

10 Qs

quiz-placeholder

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Đạo hàm

Đạo hàm

Assessment

Quiz

Mathematics

11th Grade

Practice Problem

Hard

Created by

Phạm Thuần

Used 375+ times

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Tính đạo hàm của hàm số  y=(7x5)4y=\left(7x-5\right)^4  

 y=4(7x5)3y'=4\left(7x-5\right)^3  

 y=28(7x5)3y'=-28\left(7x-5\right)^3  

 y=28(57x)3y'=-28\left(5-7x\right)^3  

 y=28(57x)3y'=28\left(5-7x\right)^3  

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Tính đạo hàm của hàm số  y=(1x3)5y=\left(1-x^3\right)^5  

 y=5x2(1x3)4y'=5x^2\left(1-x^3\right)^4  

 y=15x2(1x3)4y'=-15x^2\left(1-x^3\right)^4  

 y=3x2(1x3)4y'=-3x^2\left(1-x^3\right)^4  

 y=5x2(1x3)4y'=-5x^2\left(1-x^3\right)^4  

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Tính đạo hàm của hàm số  f(x)=2xx1f\left(x\right)=\frac{2x}{x-1}  tại điểm  x=1x=-1  

1

 12-\frac{1}{2}  

- 2

0

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Tính đạo hàm của hàm số y=x2+2x3x+2y=\frac{x^2+2x-3}{x+2}  

 y=1+3(x+2)2y'=1+\frac{3}{\left(x+2\right)^2}  

 y=x2+6x+7(x+2)2y'=\frac{x^2+6x+7}{\left(x+2\right)^2}  

 y=x2+4x+5(x+2)2y'=\frac{x^2+4x+5}{\left(x+2\right)^2}  

 y=x2+8x+1(x+2)2y'=\frac{x^2+8x+1}{\left(x+2\right)^2}  

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 Tính đạo hàm của hàm số y=x24x3y=\sqrt{x^2-4x^3} 

 y=x6x2x24x3y'=\frac{x-6x^2}{\sqrt{x^2-4x^3}}  

 y=12x24x3y'=\frac{1}{2\sqrt{x^2-4x^3}}  

 y=x12x22x24x3y'=\frac{x-12x^2}{2\sqrt{x^2-4x^3}}  

 y=x6x22x24x3y'=\frac{x-6x^2}{2\sqrt{x^2-4x^3}}  

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 Tính đạo hàm của hàm số y=12sin(π3x2)y=-\frac{1}{2}\sin\left(\frac{\pi}{3}-x^2\right) 

 y=xcos(π3x2)y'=x\cos\left(\frac{\pi}{3}-x^2\right)  

 y=12x2cos(π3x)y'=\frac{1}{2}x^2\cos\left(\frac{\pi}{3}-x\right)  

 y=12xsin(π3x)y'=\frac{1}{2}x\sin\left(\frac{\pi}{3}-x\right)  

 y=12xcos(π3x2)y'=\frac{1}{2}x\cos\left(\frac{\pi}{3}-x^2\right)  

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Tính đạo hàm của hàm số y=cos2x+1y=\cos\sqrt{2x+1}  

 y=sin2x+12x+1y'=-\frac{\sin\sqrt{2x+1}}{\sqrt{2x+1}}  

 y=sin2x+12x+1y'=\frac{\sin\sqrt{2x+1}}{\sqrt{2x+1}}  

 y=sin2x+1y'=-\sin\sqrt{2x+1}  

 y=sin2x+122x+1y'=-\frac{\sin\sqrt{2x+1}}{2\sqrt{2x+1}}  

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