Search Header Logo

ぐらぐらインテグラル①

Authored by Kenji Takei

Mathematics

11th - 12th Grade

Used 63+ times

ぐらぐらインテグラル①
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

次の不定積分を求めよ

(積分定数をCとする)

 (2x2+5x+3)dx\int_{ }^{ }\left(2x^2+5x+3\right)dx  

 23x3+52x2+x3+C\frac{2}{3}x^3+\frac{5}{2}x^2+x^3+C  

 32x3+25x2+3x+C\frac{3}{2}x^3+\frac{2}{5}x^2+3x+C  

 23x3+52x2+3x+C\frac{2}{3}x^3+\frac{5}{2}x^2+3x+C  

 4x3+5+C4x^3+5+C  

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

次の不定積分を求めよ

(積分定数をCとする)

 (x2)(2x+3)dx\int_{ }^{ }\left(x-2\right)\left(2x+3\right)dx  

 23x312x26x+C\frac{2}{3}x^3-\frac{1}{2}x^2-6x+C  

 23x3+12x26x+C\frac{2}{3}x^3+\frac{1}{2}x^2-6x+C  

 23x3+12x26x\frac{2}{3}x^3+\frac{1}{2}x^2-6x  

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

次の不定積分を求めよ

(積分定数をCとする)

 (5x33x2+3x)dx\int_{ }^{ }\left(5x^3-3x^2+3x\right)dx  

 5x43x3+3x2+C5x^4-3x^3+3x^2+C  

 53x332x2+3\frac{5}{3}x^3-\frac{3}{2}x^2+3  

 54x4x3+32x2\frac{5}{4}x^4-x^3+\frac{3}{2}x^2  

 54x4x3+32x2+C\frac{5}{4}x^4-x^3+\frac{3}{2}x^2+C  

 54x3x2+32x+C\frac{5}{4}x^3-x^2+\frac{3}{2}x+C  

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

次の不定積分を求めよ

(積分定数をCとする)

 (3)dx\int_{ }^{ }\left(-3\right)dx  

 3x+C-3x+C  

 3dx-3dx  

 3C-3C  

 3x-3x  

 x=0x=0  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

次の不定積分を求めよ

(積分定数をCとする)

 (x+3)2dx+(x+2)2dx\int_{ }^{ }\left(-x+3\right)^2dx+\int_{ }^{ }\left(x+2\right)^2dx  

 23x3x2+13x+C\frac{2}{3}x^3-x^2+13x+C  

 2x22x+13+C2x^2-2x+13+C  

 x2x+7+Cx^2-x+7+C  

 2x22x+132x^2-2x+13  

 x2x+7x^2-x+7  

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

次の条件を満たす関数 f(x)f\left(x\right)  を求めよ

 f(x)=2x2+2xf'\left(x\right)=2x^2+2x  , f(0)=1f\left(0\right)=1  

 f(x)=23x3+x2+1f\left(x\right)=\frac{2}{3}x^3+x^2+1  

 f(x)=x3+2x2+1f\left(x\right)=x^3+2x^2+1  

 f(x)=32x3+12x2+1f\left(x\right)=\frac{3}{2}x^3+\frac{1}{2}x^2+1  

 f(x)=23x2+x+1f\left(x\right)=\frac{2}{3}x^2+x+1  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

次の不定積分を求めよ

(積分定数をCとする)

 (x32x2+3x+2)dx\int_{ }^{ }\left(-x^3-2x^2+3x+2\right)dx  

 3x24x+3+C-3x^2-4x+3+C  

 14x423x3+32x2+2x+C-\frac{1}{4}x^4-\frac{2}{3}x^3+\frac{3}{2}x^2+2x+C  

 13x3+x2+3+C-\frac{1}{3}x^3+x^2+3+C  

 14x4x3+32x2+2x+C-\frac{1}{4}x^4-x^3+\frac{3}{2}x^2+2x+C  

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Microsoft

Continue with Microsoft

or continue with

Facebook

Facebook

Apple

Apple

Others

Others

By signing up, you agree to our Terms of Service & Privacy Policy

Already have an account?