What is the vector O X → \overrightarrow{OX} O X <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

4 5 a + 1 5 b \frac{4}{5}a+\frac{1}{5}b 5 4 a + 5 1 b

1 5 a + 4 5 b \frac{1}{5}a+\frac{4}{5}b 5 1 a + 5 4 b

1 4 a + 3 4 b \frac{1}{4}a+\frac{3}{4}b 4 1 a + 4 3 b

3 4 a + 1 4 b \frac{3}{4}a+\frac{1}{4}b 4 3 a + 4 1 b

What is the vector Y O → \overrightarrow{YO} Y O <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

− 2 3 a − 1 3 b -\frac{2}{3}a-\frac{1}{3}b − 3 2 a − 3 1 b

2 3 a + 1 3 b \frac{2}{3}a+\frac{1}{3}b 3 2 a + 3 1 b

− 1 3 a − 2 3 b -\frac{1}{3}a-\frac{2}{3}b − 3 1 a − 3 2 b

− 1 2 a − 1 2 b -\frac{1}{2}a-\frac{1}{2}b − 2 1 a − 2 1 b

What is the vector A Y → \overrightarrow{AY} A Y <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

− 1 3 ( a − b ) -\frac{1}{3}\left(a-b\right) − 3 1 ( a − b )

1 3 ( a + 1 3 b ) \frac{1}{3}\left(a+\frac{1}{3}b\right) 3 1 ( a + 3 1 b )

− 1 3 a + 2 3 b -\frac{1}{3}a+\frac{2}{3}b − 3 1 a + 3 2 b

− 1 3 ( a + b ) -\frac{1}{3}\left(a+b\right) − 3 1 ( a + b )

What is the vector B S → \overrightarrow{BS} B S <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

− 1 4 𝒂 + 3 5 𝒃 -\frac{1}{4}𝒂+\frac{3}{5}𝒃 − 4 1 a + 5 3 b

7 20 𝒂 \frac{7}{20}𝒂 2 0 7 a

What is the vector R S → \overrightarrow{RS} R S <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

− 7 20 𝒂 + 3 5 𝒃 -\frac{7}{20}𝒂+\frac{3}{5}𝒃 − 2 0 7 a + 5 3 b

− 1 4 𝒂 + 3 5 𝒃 -\frac{1}{4}𝒂+\frac{3}{5}𝒃 − 4 1 a + 5 3 b

7 20 𝒂 + 3 5 𝒃 \frac{7}{20}𝒂+\frac{3}{5}𝒃 2 0 7 a + 5 3 b

1 4 𝒂 + 𝒃 \frac{1}{4}𝒂+𝒃 4 1 a + b

What is the vector O T → \overrightarrow{OT} O T <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

5 6 ( a + 2 b ) \frac{5}{6}\left(a+2b\right) 6 5 ( a + 2 b )

1 6 ( a + 2 b ) \frac{1}{6}\left(a+2b\right) 6 1 ( a + 2 b )

5 ( a + 2 b ) 5\left(a+2b\right) 5 ( a + 2 b )

6 5 ( a + 2 b ) \frac{6}{5}\left(a+2b\right) 5 6 ( a + 2 b )

What are the vectors of A B → \overrightarrow{AB} A B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> and M N → \overrightarrow{MN} M N <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z">

A B → = 2 ( − m + n ) \overrightarrow{AB}=2\left(-m+n\right) A B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 2 ( − m + n ) M N → = − m + n \overrightarrow{MN}=-m+n M N <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = − m + n

A B → = − m + n \overrightarrow{AB}=-m+n A B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = − m + n M N → = 2 ( − m + n ) \overrightarrow{MN}=2\left(-m+n\right) M N <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 2 ( − m + n )

A B → = − 2 m + n \overrightarrow{AB}=-2m+n A B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = − 2 m + n M N → = 2 ( − 2 m + n ) \overrightarrow{MN}=2\left(-2m+n\right) M N <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 2 ( − 2 m + n )

M N → = − 2 m + n \overrightarrow{MN}=-2m+n M N <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = − 2 m + n A B → = 2 ( − 2 m + n ) \overrightarrow{AB}=2\left(-2m+n\right) A B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 2 ( − 2 m + n )

Year 11 IGCSE Vectors

Authored by Fiona Davidson

Mathematics

6th - 10th Grade

CCSS covered

Used 162+ times

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15 questions

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MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the column vector of b

\lceil5\rceil

\lfloor1\rfloor

$\lceil1\rceil$
$\lfloor5\rfloor$

$\lceil-5\rceil$
$\lfloor-1\rfloor$

$\lceil5\rceil$
$\lfloor-1\rfloor$

Tags

CCSS.HSN.VM.A.1

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the column vector of g

$\lceil3\rceil$
$\lfloor3\rfloor$

$\lceil0\rceil$
$\lfloor3\rfloor$

$\lceil-3\rceil$
$\lfloor0\rfloor$

$\lceil0\rceil$
$\lfloor-3\rfloor$

Tags

CCSS.HSN.VM.A.1

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the column vector of c

$\lceil3\rceil$
$\lfloor3\rfloor$

$\lceil2\rceil$
$\lfloor-3\rfloor$

$\lceil-3\rceil$
$\lfloor2\rfloor$

$\lceil3\rceil$
$\lfloor-3\rfloor$

Tags

CCSS.HSN.VM.A.2

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the vector $\overrightarrow{AD}$

a+b

-a+b

-a-b

a-b

Tags

CCSS.HSN.VM.A.2

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the vector $\overrightarrow{XZ}$

-a-b

-b+a

b-a

a-b

Tags

CCSS.HSN.VM.A.2

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the vector $\overrightarrow{NK}$

3a-b-a

3a-b

4a+b

2a-b

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the vector $\overrightarrow{CB}$

-a-b

-a+b

-b

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the vector $\overrightarrow{OX}$

$\frac{1}{5}a+\frac{4}{5}b$

$\frac{4}{5}a+\frac{1}{5}b$

$\frac{1}{4}a+\frac{3}{4}b$

$\frac{3}{4}a+\frac{1}{4}b$

Tags

CCSS.HSN-VM.B.4A

CCSS.HSN-VM.B.4B

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the vector $\overrightarrow{YO}$

$\frac{2}{3}a+\frac{1}{3}b$

$-\frac{1}{3}a-\frac{2}{3}b$

$-\frac{2}{3}a-\frac{1}{3}b$

$-\frac{1}{2}a-\frac{1}{2}b$

Tags

CCSS.HSN-VM.B.4A

CCSS.HSN-VM.B.4B

10.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the vector $\overrightarrow{AY}$

$\frac{1}{3}\left(a+\frac{1}{3}b\right)$

$-\frac{1}{3}a+\frac{2}{3}b$

$-\frac{1}{3}\left(a-b\right)$

$-\frac{1}{3}\left(a+b\right)$

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Year 11 IGCSE Vectors

What is the column vector of b

What is the column vector of g

What is the column vector of c

What is the vector AD→\overrightarrow{AD}AD

What is the vector XZ→\overrightarrow{XZ}XZ

What is the vector NK→\overrightarrow{NK}NK

What is the vector CB→\overrightarrow{CB}CB

What is the vector OX→\overrightarrow{OX}OX

What is the vector YO→\overrightarrow{YO}YO

What is the vector AY→\overrightarrow{AY}AY

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