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Sum/Difference & Double Angle Formulas

Authored by Elizabeth Anderson

Mathematics

10th - 12th Grade

CCSS covered

Used 204+ times

Sum/Difference & Double Angle Formulas
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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Find the exact value of the expression.
 sin⁡(5π12)cos⁡(π4)−cos⁡(5π12)sin⁡(π4)\sin\left(\frac{5\pi}{12}\right)\cos\left(\frac{\pi}{4}\right)-\cos\left(\frac{5\pi}{12}\right)\sin\left(\frac{\pi}{4}\right)  

 12\frac{1}{2}  

 −12-\frac{1}{2}  

 −22-\frac{\sqrt{2}}{2}  

 −32-\frac{\sqrt{3}}{2}  

Tags

CCSS.HSF.TF.C.9

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Given  sin⁡α=−35, cos⁡α=−45\sin\alpha=-\frac{3}{5},\ \cos\alpha=-\frac{4}{5}   and  cos⁡β=255, sin⁡β=−55\cos\beta=\frac{2\sqrt{5}}{5},\ \sin\beta=-\frac{\sqrt{5}}{5}   
Find the exact value of sin (α+β):

0

 −2525-\frac{2\sqrt{5}}{25}  

 2−64\frac{\sqrt{2}-\sqrt{6}}{4}  

 84\frac{\sqrt{8}}{4}  

Tags

CCSS.HSF.TF.C.9

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Given tan α = 3/4 and tan β = (-1/2)

Please find the sum and difference:

tan (α-β)=

−10525-\frac{10\sqrt{5}}{25}

−2525-\frac{2\sqrt{5}}{25}

2−64\frac{\sqrt{2}-\sqrt{6}}{4}

2

Tags

CCSS.HSF.TF.C.9

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Find the exact value. 
 cos⁡(265°−25°)\cos\left(265\degree-25\degree\right)  

 5312\frac{53}{12}  

 −32-\frac{\sqrt{3}}{2}  

 −12-\frac{1}{2}  

 32\frac{\sqrt{3}}{2}  

Tags

CCSS.HSF.TF.C.9

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Use a sum or difference formula to find an exact value of sin 105º

32\frac{\sqrt{3}}{2}

−2−64\frac{-\sqrt{2}-\sqrt{6}}{4}

2+64\frac{\sqrt{2}+\sqrt{6}}{4}

2−32-\sqrt{3}

Tags

CCSS.HSF.TF.C.9

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Please select the correct solution

cos 2 x + sin 2 x=

(It's on your reference sheet!!)

1

csc 2 x + sec 2 x

sin 2 x

1 - sin 2 x

Tags

CCSS.HSF.TF.C.8

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Use a double-angle identity to find the exact value of each expression

cos θ = 4/5 and 270° < θ < 360°

Find sin 2θ

−15-\frac{1}{5}

2425\frac{24}{25}

−2425-\frac{24}{25}

−2524-\frac{25}{24}

Tags

CCSS.HSF.TF.C.9

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