Log Properties

Write log_b(xy) as two logs

• log_bx+log_by
• log_bx-log_by
• log_bx*log_by
• log_bx/log_by

Write log_b(x/y) as two logs

• log_bx-log_by
• log_bx+log_by
• log_bx*log_by
• log_bx/log_by

Rewrite log_b(xⁿ)

• nlog_bx
• (log_bx)ⁿ
• xⁿlog_bx
• log_b(xⁿ)

Expand

• A
• B
• C
• D

• log (a⁵ + b²⁵)
• log (a⁵ − b²⁵)
• log (ab²⁵)
• log (a⁵/b²⁵)

Write as a single logarithm:

log(30)-log(6)

• -6log(30)

• log(24)

• log(-24)

• log(5)

Using the change of base rule, what is this logarithm equivalent to?

• A
• B
• C
• D

Solve

log₂(x + 5) = 3

• 3

• 4

• 5

• 6

Solve

log₂(x + 2) + log₂x = 3

• -4, 2

• -2, 4

• 2

• 1

Solve

2³ⁿ = 4

• 2

• 3

• 2/3

• 4

Tags

CCSS.6.EE.B.7