Solving Quadratics by Factoring

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

What is the first question you ask yourself when factoring a polynomial? 

• How many terms does it have? 
• Is there a GCF? 
• What strategy should I use? 
• Why do I have to learn this?!?!?!

Tags

CCSS.HSA.SSE.A.2

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }
• { 3, -6 }
• { -3, -6 }
• { 3, 6 }

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 2x - 24 = 0

• x = -6, x = 4
• x = 6, x = -4
• x = 12, x = -2
• x = 8, x = -3

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 9x + 20 = 0

• x = -2, x = -10
• x = -3, x = -4
• x = -4, x = -5
• x = -4, x = -6

Tags

CCSS.HSA-REI.B.4B

Solve.
n² - 2n = 0

• n = 2 and 0
• n = -2 and 0
• n = 2
• n = 0

Tags

CCSS.HSA-REI.B.4B

Factor x²-16

• (x+4)²

• (x-4)²

• (x-16)(x+16)

• (x-4)(x+4)

Tags

CCSS.HSA.APR.C.4

Solve by factoring:  2x²+ 7x + 6 = 0

• x= 3/2 and x = 2
• x = -3/2 and x = -2
• x = 6 and x = 7
• x = -6 and x = -7

Tags

CCSS.HSA-REI.B.4B

Solve 3x²+7x-6 = 0

• x = 3, x = -3/2

• x = 2/3, x = -7

• x = 3, x = -2/3

• x = -3, x = 2/3

Tags

CCSS.HSA-REI.B.4B

Solve 5x² = 13x+6

• x = -3, x = 2/5

• x = -2, x = 15

• x = 3, x = -2/5

• x = 2, x = -15

Tags

CCSS.HSA-REI.B.4B