1 2 − i = \frac{1}{2-i}= 2 − i 1 =

2 5 + 1 5 i \frac{2}{5}+\frac{1}{5}i 5 2 + 5 1 i

2 5 − 1 5 i \frac{2}{5}-\frac{1}{5}i 5 2 − 5 1 i

2 3 + 1 3 i \frac{2}{3}+\frac{1}{3}i 3 2 + 3 1 i

2 3 − 2 3 i \frac{2}{3}-\frac{2}{3}i 3 2 − 3 2 i

複數 Quiz: 10 Practice Questions

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

$\left(4+2i\right)+\left(3-i\right)=$

$7+i$

$7-i$

$12-2i$

$12-2i^2$

2.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

$\left(5-i\right)-\left(2+3i\right)=$

$3-4i$

$3+2i$

$7-4i$

$7+2i$

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$\left(4+i\right)\left(4-i\right)=$

17

$16-i$

15

$9$

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$4-2i$ 的虛部是

4

$-4$

2

$-2$

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$\left(2+3i\right)^2$ 的實部是

13

$-5$

12

4

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

將 $\frac{2+i}{3-2i}$ 有理化，應於分子和分母同時乘以哪一個複數？

$2+i$

$2-i$

$3+2i$

$3-2i$

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$\frac{1}{2-i}=$

$\frac{2}{5}+\frac{1}{5}i$

$\frac{2}{5}-\frac{1}{5}i$

$\frac{2}{3}+\frac{1}{3}i$

$\frac{2}{3}-\frac{2}{3}i$

8.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\left(1+ai\right)\left(a+i\right)$ 中的虛部是

$a^2+1$

$2a+1$

0

2

9.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

$\frac{a-i}{a+i}$ 的實部是

$\frac{a^2-1}{a^2+1}$

1

$\frac{2a}{a^2-1}$

$\frac{-2a}{a^2+1}$

10.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$i^{2020}=$

1

$-1$

$i$

$-i$

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複數

(4+2i)+(3−i)=\left(4+2i\right)+\left(3-i\right)=(4+2i)+(3−i)=

(5−i)−(2+3i)=\left(5-i\right)-\left(2+3i\right)=(5−i)−(2+3i)=

(4+i)(4−i)=\left(4+i\right)\left(4-i\right)=(4+i)(4−i)=

4−2i4-2i4−2i 的虛部是

(2+3i)2\left(2+3i\right)^2(2+3i)2 的實部是

將 2+i3−2i\frac{2+i}{3-2i}3−2i2+i​ 有理化，應於分子和分母同時乘以哪一個複數？

12−i=\frac{1}{2-i}=2−i1​=

(1+ai)(a+i)\left(1+ai\right)\left(a+i\right)(1+ai)(a+i) 中的虛部是

a−ia+i\frac{a-i}{a+i}a+ia−i​ 的實部是

i2020=i^{2020}=i2020=

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Popular Resources on Wayground

Discover more resources for Mathematics

$\left(4+2i\right)+\left(3-i\right)=$

$\left(5-i\right)-\left(2+3i\right)=$

$\left(4+i\right)\left(4-i\right)=$

$4-2i$ 的虛部是

$\left(2+3i\right)^2$ 的實部是

將 $\frac{2+i}{3-2i}$ 有理化，應於分子和分母同時乘以哪一個複數？

$\frac{1}{2-i}=$

$\left(1+ai\right)\left(a+i\right)$ 中的虛部是

$\frac{a-i}{a+i}$ 的實部是

$i^{2020}=$