Differential Equations

Given the differential equation dP/Dt=5P

A) Find the general solution for P to the differential equation

B)Find the particular solution for P to the differential equation given P(0)= 418

• A) P=Ce^5t

  B) P= 5e^418t

• A) P=Ce^5t

  B) P= 418e^5t

• A) P=Ce^t

  B) P= 418e^t

• A) P=Ce^10t

  B) P= 418e^10t

Tags

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

CCSS.HSF.LE.B.5

dy/dx = 2x/e^2y find the general solution

• y = ln (2x/2 + C)

  2

• y = ln(2x/2)+c

• y = e^2x+c

• y = mx+b

2. Solve the differential equation

𝑑𝑦/𝑑𝑡 =3𝑡²/𝑦 with initial condition

𝑦(2) = 0.

• 𝑦 = ln(15t)

• 𝑦 = 16t³

• 𝑦 = (2𝑡³ − 16)^1/2

• 𝑦 = (2𝑡³ −16)

Tags

CCSS.HSA.SSE.A.1

CCSS.HSF.BF.B.5

dy/dx= x √y

Find the general solution

• √y = ln|4x| + c

• √y = (x)^-1 + c

• 2y^1/2 = ln|x| + c

• 1/2y^1/2 = ln|x| + c

dp/dy = (4y)^-1find the general solution

• p= 1/5y^5/4 + c

• p= 1/4ln|4y| + c

• p= 1/8y² + c

• p= 1 + c

  4y

dy/dx = 4x/y. Suppose y(0)=1

The particular solution is

• B

• C

• D

• E

Tags

CCSS.HSA.REI.A.1

Find the particular solution for y if dy/dx = 2x√y and y = 4 when x = 3.

• 2√y = x² + C

• y = (x² + 25)²/4

• y = (x²/2-5/2)^1/2

• y = x⁴/4

Tags

CCSS.HSA-REI.B.4B