Solving Quadratics by Factoring

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }
• { 3, -6 }
• { -3, -6 }
• { 3, 6 }

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 2x - 24 = 0

• x = -6, x = 4
• x = 6, x = -4
• x = 12, x = -2
• x = 8, x = -3

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 9x + 20 = 0

• x = -2, x = -10
• x = -3, x = -4
• x = -4, x = -5
• x = -4, x = -6

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 7x + 12 = 0

• x = -2, x = -10
• x = -3, x = -4
• x = -4, x = -5
• x = -4, x = -6

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 13x + 12 = 0

• x = -1, x = -12
• x = -1, x = -24
• x = -2, x = -6
• x = -2, x = -12

Tags

CCSS.HSA-REI.B.4B

Solve
6x² + 17x + 12 = 0

• x = -4/3, x = -3/2
• x = 9, x = 8
• x = 4, x = 3
• x = -4, x = -3

Tags

CCSS.HSA-REI.B.4B

Solve
 2x² - 3x - 2 = 0

• x = 1, x = -1
• x = -1/2, x = 2
• x = 1/2, x = 2
• x = 1/2, x = 1

Tags

CCSS.HSA-REI.B.4B

Solve
5x² - 28x + 32 = 0

• x = 10/3, x = -6
• x = 8, x = 4/5
• x = 8/5, x = 4
• x = 8/5, x = -7

Tags

CCSS.HSA-REI.B.4B

Solve
 3x² + 5x - 12 = 0

• x = -4/3, x = 3
• x = 4/3, x = -3
• x = -1, x = 4
• x = 1, x = -4

Tags

CCSS.HSA-REI.B.4B