AP Calc AB Review for QZ 32-33

AP Calc AB Review for QZ 32-33

11th Grade - University

10 Qs

quiz-placeholder

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AP Calc AB Review for QZ 32-33

AP Calc AB Review for QZ 32-33

Assessment

Quiz

Mathematics

11th Grade - University

Practice Problem

Easy

integration and transcendentals, integration of transcendentals, integration and motion

Standards-aligned

Created by

Todd Nelson

Used 14+ times

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

1xdx=\int\frac{1}{x}dx=

lnx+C\ln\left|x\right|+C

1x2+C-\frac{1}{x^2}+C

1x2+C\frac{1}{x^2}+C

1

Tags

integration and transcendentals

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt


xe3x2dx=\int_{ }^{ }xe^{-3x^2}dx=

16e3x2+C-\frac{1}{6}e^{-3x^2}+C

13e3x2+C\frac{1}{3}e^{-3x^2}+C

13e3x2+C-\frac{1}{3}e^{-3x^2}+C

16e3x2+C\frac{1}{6}e^{-3x^2}+C

Tags

integration of transcendentals

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

4x2x2+6 dx=\int_{ }^{ }\frac{4x}{2x^2+6}\ dx=

ln2x2+6+C\ln\left|2x^2+6\right|+C

ln(2x2+6)(4x)+C\ln\left(2x^2+6\right)\left(4x\right)+C

12x2+6+C\frac{1}{2x^2+6}+C

1(2x2+6)2+C\frac{1}{\left(2x^2+6\right)^2}+C

Tags

integration and transcendentals

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

A particle moves along an axis so that at any time t>0t>0 , its velocity is given by v(t)=46t2v\left(t\right)=4-6t^2 . If the particle is at position p=7p=7 when t=1t=1 , what is the position of the particle at t=2t=2 ?

-10

-5

-3

3

Tags

integration and motion

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

2xx2+1 dx=\int_{ }^{ }\frac{2x}{x^2+1}\ dx=

ln(x2+1)+C\ln\left(x^2+1\right)+C

ln2x+C\ln\left|2x\right|+C

1(x2+1)2+C\frac{1}{\left(x^2+1\right)^2}+C

12x+C\frac{1}{2x}+C

Tags

integration and transcendentals

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

exx dx=\int_{ }^{ }\frac{e^{\sqrt{x}}}{\sqrt{x}}\ dx=

2ex+C2e^{\sqrt{x}}+C

12ex+C\frac{1}{2}e^{\sqrt{x}}+C

2xex+C2\sqrt{x}e^{\sqrt{x}}+C

ex+Ce^{\sqrt{x}}+C

Tags

integration of transcendentals

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

 cot(ab) db=\int_{ }^{ }\cot\left(ab\right)\ db=  

 1acsc2(ab)+C-\frac{1}{a}\csc^2\left(ab\right)+C  

 1alnsin(ab)+C\frac{1}{a}\ln\left|\sin\left(ab\right)\right|+C  

 1blncos(ab)+C\frac{1}{b}\ln\left|\cos\left(ab\right)\right|+C  

 1blnsin(ab)+C\frac{1}{b}\ln\left|\sin\left(ab\right)\right|+C  

Tags

integration and transcendentals

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