Solving Quadratic Equations

Solve by completing the square.
x² + 4x= 12

• x = 2 and -2
• x = -6 and 2
• x = 6 and -2
• x = 1 and -1

Tags

CCSS.HSA-REI.B.4B

ax²+bx+c=0  is the standard form of a quadratic equation.

• True
• False

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.4

Determine the values of
a, b, and c for
the quadratic equation: 
4x² – 8x = 3

• a = 4, b = -8, c = 3
• a = 4, b =-8, c =-3
• a = 4, b = 8, c = 3
• a = 4, b = 8, c = -3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

Factor x²-11x+24

• (x-3)(x-8)
• (x-2)(x-12)
• (x+3)(x+8)
• (x+2)(x+12)

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Solve for the values of x:
(x + 2)(x - 3) = 0

• { 2, 3 }
• { -2, -3 }
• { 2, 3 }
• { -2, 3 }

Tags

CCSS.HSA.REI.B.4

Solve by factoring

• -4, 2

• -2, 4

• -16

• -4

Tags

CCSS.HSA-REI.B.4B

Solve using the Quadratic Formula:

2x² + 2x − 12 = 0

• x = −2, 3

• x = 2, 3

• x = 2, −3

• x = −2, −3

Tags

CCSS.HSA-REI.B.4B

Solve by factoring. (HINT: Factor GCF 1st)

• x = 3, x = -6

• x = 0, x = 2

• x = 2, x = 3

• x = -2, x = 1

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

What number added would make a perfect square trinomial?

x² - 8x + ______

• -4

• -64

• 12

• 16

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3