2.3: Long and Synthetic Division

Divide using synthetic division 
(2x³ + 4x² - 5) by (x + 3).

• 2x² + 2x - 4  R(-12)
• 2x² - 2x + 6  R(-23)
• 2x² - 2x + 8  R(-20)
• 2x² - 4x + 1  R0

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.D.6

• x - 7
• x² - 7
• x + 7
• x² + 3x - 54

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.REI.B.4

• x + 5 + (2/2x - 4)
• x - 8
• x - 5 + (3/2x - 4)
• x + 5

Tags

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

CCSS.HSA.SSE.B.3

What is the proper way to write the answer for the following problem?

• 2x³-x²-25x+12

• 2x⁴-x³-25x²-12x+0

• 2x³-x²-25x-12

• 2x⁴-x³-25x²-12x-0

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.B.3

Cam divided (x⁴ + 3x² - 4x - 2) by factor of (x-2) using synthetic division. His work is shown above. Which best describes his mistake?

• Cam wrote the remainder incorrectly.

• Cam did not use a zero place holder for the x³ term.

• Cam added instead of subtracting the rows.

• Cam should have used -2 as his division since the factor was x-2.

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.D.6

(2x³ - 5x² + 3x + 7) ÷ (x - 2)

• 2x³ - x² + x + 9
• 2x² - x + 1
• 2x² - x + 1 + 9/x-2
• 2x² - 9x - 15 - 23/x-2

Tags

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

• 2x - 5
• x - 4 + (3/4x - 5)
• 2x + 4 + (3/4x - 5)
• 2x + 4

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

CCSS.HSA.SSE.A.2

• -3x² + 3x + 2
• x² - 3x - 2
• -3x² + 2
• x² + 3x + 2

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

2x³ - 5x² + 3x + 7 ÷ x - 2

• 2x³ - x² + x + 9
• 2x² - x + 1
• 2x² - x + 1 + 9/x-2
• 2x² - 9x - 15 - 23/x-2

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

CCSS.HSA.SSE.B.3

• 4x

• 21

• 2x-1

• 10x

Tags

CCSS.HSA.APR.D.6