System of Equations - Elimination - Part A and B

Solve the system of equations using elimination.

 $3x+y=–14$  

 $–2x–y=9$  

•  $(-5,1)$  

•  $(5,-1)$  

•  $(1,4)$  

•  $(-1,4)$  

Solve the system of equations using elimination. 

 $x+3y=18$  
 $–x–4y=–25$  

•  $(3,7)$  

•  $(-3,7)$  

•  $(7,-3)$  

•  $(-3,-7)$  

Solve the system of equations: 
 $3x+y=–21$  
 $x+y=–5$   

•  $(-3,8)$  

•  $(8,-3)$  

•  $(3,-8)$  

•  $(-8,3)$  

Solve by elimination:

 $9x-4y=7$  
 $x-4y=-17$  

•  $(-1,5)$  

•  $(-7,5)$  

•  $(7,5)$  

•  $(3,5)$  

What would be the first step in finding the solution using elimination?
 $2x+2y=-2$  
 $3x-2y=12$  

• you cannot solve this using eliminiation

• cross out the 2x and 3x

• add the 2 equations to eliminate 2y and -2y

• change each equation to slope intercept form and graph

What is the first step in solving the following system of equations using elimination?
 $x+2y=-19$  
 $5x+2y=1$  

• add the two equations to eliminate 2 y and 2y

• add  $-1$  to both equations

• you can NOT solve this system using elimination method

• multiply the second equation by  $-1$