y = 5 x − 3 y=5x-3 y = 5 x − 3

y = 1 5 x − 3 y=\frac{1}{5}x-3 y = 5 1 x − 3

y = − 3 x + 3 y=-3x+3 y = − 3 x + 3

Koeficijent smjera jednak 2 i odsječak na osi y jednak -1 ima pravac

2 x − y − 1 = 0 2x-y-1=0 2 x − y − 1 = 0

2 x + y + 1 = 0 2x+y+1=0 2 x + y + 1 = 0

2 x − y + 1 = 0 2x-y+1=0 2 x − y + 1 = 0

− 2 x + y − 1 = 0 -2x+y-1=0 − 2 x + y − 1 = 0

Odredi pravce koji maju jednake odsječke na koordinatnim osima

x − 2 y = 4 x-2y=4 x − 2 y = 4

− 3 x + 6 y = − 12 -3x+6y=-12 − 3 x + 6 y = − 1 2

− 3 x + 2 y = 6 -3x+2y=6 − 3 x + 2 y = 6

3 x − y = 2 3x-y=2 3 x − y = 2

jednadžba pravca

Authored by blaženka žigolić

Mathematics

11th Grade

Used 40+ times

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MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Koeficijent smjera pravca 2x+y=3 je:

-2

$\frac{1}{2}$

$-\frac{1}{2}$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jednadžba pravca 2x+y=0 zapisana je u:

segmentnom obliku

eksplicitnom obliku

implicitnom obliku

MULTIPLE SELECT QUESTION

2 mins • 1 pt

Izaberi sve točke koje pripadaju pravcu 2x+y=3?

(2, -1)

(2,1)

(1,3)

(1,1)

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jednadžba pravca sa slike je

$\frac{x}{3}+\frac{y}{1}=1$

$y=\frac{1}{3}x+1$

$y=3x+1$

$\frac{x}{-3}+\frac{y}{-1}=1$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Presjek pravac $-2x+3y+12=0$ s osi ordinata je

(6,-4)

(6,0)

(0,-4)

(0,4)

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Kojem pravcu pripada točka T(1,-4)

$y=2x-2$

$y=2x-4$

$y=-2x-2$

$y=-2x-4$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Pravac na slici je

$y=5x-3$

$y=\frac{1}{5}x-3$

$y=x-3$

$y=-3x+3$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Pravac $2x-4y-2=0$ s koordinatnim osima zatvara trokut površine

$\frac{1}{4}$

$\frac{1}{2}$

10.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Za koji broj $\alpha$ je pravac $\left(\alpha+1\right)x+\left(2-\alpha\right)y+7=0$ usporedan s osi x

-1

-2

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jednadžba pravca

Koeficijent smjera pravca 2x+y=3 je:

Jednadžba pravca 2x+y=0 zapisana je u:

Izaberi sve točke koje pripadaju pravcu 2x+y=3?

Jednadžba pravca sa slike je

Presjek pravac −2x+3y+12=0-2x+3y+12=0−2x+3y+12=0 s osi ordinata je

Kojem pravcu pripada točka T(1,-4)

Pravac na slici je

Pravac 2x−4y−2=02x-4y-2=02x−4y−2=0 s koordinatnim osima zatvara trokut površine

Nagib pravca x+4y+3=0 je

Za koji broj α\alphaα je pravac (α+1)x+(2−α)y+7=0\left(\alpha+1\right)x+\left(2-\alpha\right)y+7=0(α+1)x+(2−α)y+7=0 usporedan s osi x

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Presjek pravac $-2x+3y+12=0$ s osi ordinata je

Pravac $2x-4y-2=0$ s koordinatnim osima zatvara trokut površine

Za koji broj $\alpha$ je pravac $\left(\alpha+1\right)x+\left(2-\alpha\right)y+7=0$ usporedan s osi x