Unit 15 Test Review

Expand

• A
• B
• C
• D

Tags

CCSS.HSA.SSE.A.2

CCSS.HSF.BF.B.5

Expand

• A
• B
• C
• D

Tags

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.B.5

CCSS.HSF.IF.C.8

CCSS.HSF.LE.A.4

Condense

• A
• B
• C
• D

Tags

CCSS.HSA.SSE.A.1

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

Condense

• A
• B
• C
• D

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

Condense

• A

• B

• C

• D

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

Condense

• log xyz³
• log (xy/z³)
• log x + log y + log z³
• log x³y³z³

Tags

CCSS.HSA.SSE.B.3

Expand

• log₈ x + log₈ y + log₈ z
• 5log₈ x + 5log₈ y + 5log₈ z
• log₈ xy + 5log₈ z
• log₈ x + log₈ y + 5log₈ z

Tags

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.B.5

CCSS.HSF.IF.C.8

Solve for x using the same base method.
3^x-20 = 27

• 17
• 27
• -7
• 23

Tags

CCSS.HSA.CED.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

Solve for a:
5^{a + 2} = 1/125

• -1
• -6/7
• -5
• 4

Tags

CCSS.HSF.LE.A.4

To solve 8 = 2^5x+7, you would need to re-write 8 as what base?

• 8
• 4
• 2
• Cannot be determined

Tags

CCSS.8.EE.A.1