Quantitative chemistry

Quantitative chemistry

9th - 12th Grade

15 Qs

quiz-placeholder

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Quantitative chemistry

Quantitative chemistry

Assessment

Quiz

Chemistry

9th - 12th Grade

Medium

Created by

Eva Matuskova

Used 83+ times

FREE Resource

15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Number of moles in 12.4 t of NaNO3 ÷ number of moles in 12.4 t of NaCl =

7.0

0.69

49.1

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Two students complete the synthesis of paracetamol from 4-aminophenol as shown by the equation on the picture.

Both students react 2 moles of 4-aminophenol with excess ethanoyl chloride.


Student 1 makes 1.5 moles of paracetamol. Student 2 makes 220 g of paracetamol.

Which student has the better percentage yield?

(Don't worry about the complicated names, use the molecular formulas.)

Student 1, 76 %

Student 1, 75 %

Student 2, 74 %

Student 2, 73 %

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

According to Avogadro’s Law, as long as the pressure and temperature are kept the same, equal volumes of gases contain equal numbers of moles of gas. Under standard temperature and pressure (273 K and 101,325 Pa) 1 mole of any gas has a volume of 22.4 dm3. Use Avogadro’s law to find out which gas syringe contain identical numbers of moles of gas as the syringe A (on the picture).

Syringe F

Syringe G

Syringe H

Syringe I

Syringe J

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

In the following equation, what is the molar ratio between hydrochloric acid and copper(II) oxide?


2 HCl + CuO → CuCl2 + H2O

1 : 2

2 : 1

1 : 1

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the empirical formula of octane C8H18?

CH2

C4H9

C8H18

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

In an experiment, the actual yield is 8.4 g but the theoretical yield is 17.0 g. what is the percentage yield?

24.7 %

50.6 %

49.4 %

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

When the equation below is balanced, what is the coefficient for oxygen?


__C2H2(g) + __O2(g) → __ CO2(g) + __ H2O(g)

2

3

4

5

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