Calculus 4-1-20

∫(4 - 18x)dx

• F(x) = -18
• F(x) = 4x - 9x²
• F(x) = 4x - 9x² + C
• F(x) = (4 - 18x)² /2 + C

Given v(t) = x^-9, find the general equation for the antiderivative.

• (1/8)x^-8 + C
• (-1/8)x^-8 + C
• (1/10)x¹⁰
• (-1/8)x^-8

∫ x(x² - 4) dx

• x²/2(x³/3 - 4x) + C
• .25x⁴ -2x² + C
• 3x²- 4 + C
• x⁴ - 4x² + C

If f'(x) = 4x and f(1) = 6, then f(2) =

• 6

• 8

• 9

• 12

Tags

CCSS.HSF.IF.A.2

∫cscxcotx dx =

• cscx + C
• -cscx + C
• cotx + C
• -cotx + C

• -3x+C
• 0
• -3x
• -1/3x+C

Integrate:

• x^1/2 + C

• ¹/_(2√x) + C

• ³/₂*x^3/2 + C

• ²/₃*x^3/2 + C

Find the equation for the velocity of an object whose acceleration is equal to 4x+14.

• 2x² + 14x + C
• 4 + C
• 2x³/3+7x²
• 2x³/3+7x²+C

The position function x(t)=7t²-18t-7 is given. What is the velocity function?

• v(t)=14t-18
• v(t)=14t+18
• v(t)=18t-14
• v(t)=18t+14
  

Another word for 'integral' is .. .

• Constant
• Derivative
• Antiderivative
• Theorem