DL: W2 - Adding and Subtracting Rational Functions

Determine the solution(s), if any. 

*Check for extraneous solution(s)    $\frac{2}{x+1}=\frac{3}{2x-5}$  

•  $x=-1$  

•  $x=13$  

•  $x=\frac{5}{2}$  

•  $x=-13$  

Tags

CCSS.HSA.REI.A.2

Determine the solution(s), if any. 

*Check for extraneous solution(s)    $\frac{x^2}{x^2-9}=\frac{4x}{x+3}$  

•  $x=4$  

•  $x=0,\ 3$  

•  $x=3$  

•  $x=0,\ 4$  

Tags

CCSS.HSA.REI.A.2

Determine the solution(s), if any. 

*Check for extraneous solution(s)    $\frac{4}{x-3}-\frac{2}{x}=1$  

•  $x=-1$  

•  $x=-6,\ 1$  

•  $Solution\left(s\right)\ are\ extraneous;\ no\ solution\left(s\right)$  

•  $x=-1,\ 6$  

Tags

CCSS.HSA.REI.A.2

Determine the solution(s), if any. 

*Check for extraneous solution(s)    $\frac{10}{x\left(x-2\right)}+\frac{4}{x}=\frac{5}{x-2}$  

•  $x=2$  

•  $x=-2$  

•  $Solution\left(s\right)\ are\ extraneous;\ no\ solution\left(s\right)$  

•  $x=1$  

Tags

CCSS.HSA.REI.A.2

Determine the solution(s), if any. 

*Check for extraneous solution(s)    $\frac{3}{x-4}-\frac{3}{x}=1$  

•  $x=-6,\ 2$  

•  $x=-2,\ 6$  

•  $Solution\left(s\right)\ are\ extraneous;\ no\ solution\left(s\right)$  

•  $x=-2$  

Tags

CCSS.HSA.REI.A.2

Determine the solution(s), if any. 

*Check for extraneous solution(s)    $\frac{3}{x+2}=\frac{4}{3x-5}$  

•  $x=18$  

•  $x=23$  

•  $x=\frac{23}{5}$  

•  $x=5$  

Tags

CCSS.HSA.REI.A.2

Determine the solution(s), if any. 

*Check for extraneous solution(s)    $\frac{x^2}{x^2-25}=\frac{5x}{x+5}$  

•  $Solution\left(s\right)\ are\ extraneous;\ no\ solution\left(s\right)$  

•  $x=0,\ \frac{25}{4}$  

•  $x=0$  

•  $x=0,\ 4$  

Tags

CCSS.HSA.REI.A.2

Determine the solution(s), if any. 

*Check for extraneous solution(s)    $\frac{1}{x+3}+\frac{2}{x}=\frac{-\ 3}{x\left(x+3\right)}$  

•  $x=0,\ 3$  

•  $x=3$  

•  $Solution\left(s\right)\ are\ extraneous;\ no\ solution\left(s\right)$  

•  $x=-3$  

Tags

CCSS.HSA.REI.A.2

Determine the solution(s), if any. 

*Check for extraneous solution(s)    $\frac{18}{x^2-8x+15}=\frac{-3x}{x-3}$  

•  $x=-1,\ 6$  

•  $x=-3$  

•  $x=2$  

•  $x=2,\ 5$  

Tags

CCSS.HSA.REI.A.2

Determine the solution(s), if any. 

*Check for extraneous solution(s)    $\frac{x}{x-2}+\frac{1}{x-4}=\frac{2}{x^2-6x+8}$  

•  $x=-1,\ 4$  

•  $x=4$  

•  $Solution\left(s\right)\ are\ extraneous;\ no\ solution\left(s\right)$  

•  $x=-1$  

Tags

CCSS.HSA.REI.A.2