Solving Trig Equations

Choose a good way to start solving this equation

tanx sin²x = 2 tanx

• divide tanx from both sides

• factor out tanx

• subtract 2 tanx from the left and then factor tanx out

• cancel sin²x out

Solve on the domain [0, 2π)

0 = sinx(sinx − 1)

• 0, π

• 0, π, ½π

• ½π

• 0, 90, 270

Which is a correct way to solve the equation

cosx(2cosx − 3) = 0?

• divide cos x from both sides

• set each factor equal to 0 and solve

• distribute cosx into the parentheses

• guess and hope for the best

Solve on the domain [0, 2π)

tan(x)+1=2

• 0 and π

• 3π/4 and 7π/4

• π/4 and 5π/4

• 3π/4 and 5π/4

Solve on the domain [0, 2π)

2cos²θ -1 = 0

• θ = π /4, 7π /4

• θ = π /4, 3π /4

• θ = 3π /4, 5π /4

• θ = π /4, 3π /4, 5π /4, 7π /4

Tags

CCSS.HSF.TF.B.7

Solve on the domain [0, 2π)
1/2sec x - 1 = 0

• π/6, 5π/6
• π/3, 5π/3
• 2π/3, 4π/3
• 7π/6, 11π/6

Tags

CCSS.HSF.TF.B.7

Solve on the domain [0, 2π)
4sin²x = 3

• π/6, 11π/6
• π/3, 2π/3
• π/6, 5π/6, 7π/6, 11π/6
• π/3, 2π/3, 4π/3, 5π/3

Tags

CCSS.HSF.TF.B.7

Solve on the domain [0, 2π)
2sin x cos x = √2 cos x

• π/2, 3π/2
• 0, π/4, 3π/4
• π/2, 3π/2, π/4, 3π/4
• No solution

Tags

CCSS.HSF.TF.B.7

• A
• B
• C
• D

Tags

CCSS.HSF.TF.B.7

• A
• B
• C
• D

Tags

CCSS.HSF.TF.B.7