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transformasi geometri kelas xi

Authored by Fitria Faiqa

Mathematics

11th Grade

Used 98+ times

transformasi geometri kelas xi
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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

DIketahui sebuah titik A'(3,-13) adalah bayangan titik A oleh translasi  T=10,7T=\lceil-10,7\rceil . Koordinat titik A adalah ....

A (13, -20)

A (13,-4)

A (4, 20)

A (-5, -4)

A (-5, -20)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Bayangan titik B (-1, 4) jika direfleksikan terhadap garis  y=xy=-x  adalah ....

A' (-4, 1)

A' (4, 1)

A' (4, -1)

A' (4,3)

A' ( -4, -1)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Bayangan titik P (5, 4) jika didilatasikan dengan titik pusat (-2, -3) dengan faktor skala - 4 adalah ....

P' (-30, -31)

P' ( -30, 7)

P' ( -26, -1)

P' (-14, -1)

P' ( -14, -7)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Bayangan titik  Q (2, 3)Q\ \left(2,\ -3\right)  oleh rotasi  [O, 90°]\left[O,\ 90\degree\right]  adalah ....

Q' (2, 3)

Q' (-3, 2)

Q (-2, 3)

Q' (3, 2)

Q (-3, -2)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Bayangan titik B (4,8) direfleksikan terhadap sumbu X kemudian dilanjutkan dengan dilatasi  [O,12]\left[O,\frac{1}{2}\right]  adalah ....

B'' (-2,4)

B" ( -2,4)

B" (8, -2)

B" (-8,4)

B' (-8, -4)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Jika persamaan garis lurus  y=2x+3y=2x+3  , maka persamaan garis lurus yang dihasilkan oleh translasi  T=(3,2)T=\left(3,2\right)  adalah ....

y = 3x

y = 2x + 6

y = 2x - 6

y = 2x - 4

y = 2x - 1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Bayangan garis y = 5x + 4 oleh rotasi  [O,90°]\left[O,90\degree\right]  adalah ....

 x - 5y – 4 = 0

x + 5y + 4 = 0

5x + 5y – 4 = 0

5x - 5y – 4 = 0

x + 5y – 4 = 0

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