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Solving Exponential Equations (Using Logs)

Authored by Herminia Gaxiola

Mathematics

9th - 10th Grade

CCSS covered

Used 87+ times

Solving Exponential Equations (Using Logs)
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10 questions

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1.

FILL IN THE BLANK QUESTION

2 mins • 1 pt

Solve:  7x=127^x=12 
Round your answer to two decimal places.



(a)  

Tags

CCSS.HSF.LE.A.4

2.

FILL IN THE BLANK QUESTION

3 mins • 1 pt

Solve:  103x1=510^{3x}-1=5  
Round your answer to two decimal places.

(a)  

Tags

CCSS.HSF.LE.A.4

3.

FILL IN THE BLANK QUESTION

3 mins • 1 pt

Solve:  3x+5=153^{x+5}=15  
Round your answer to two decimal places.

(a)  

Tags

CCSS.HSF.LE.A.4

4.

MULTIPLE SELECT QUESTION

3 mins • 1 pt

Solve:  2e3x=162e^{3x}=16  
Select the first incorrect step in solving this equation.

STEP 1: 2e3x2=162\frac{2e^{3x}}{2}=\frac{16}{2}  

STEP 2: ln(e3x)=ln(8)\ln\left(e^{3x}\right)=\ln\left(8\right)  

STEP 3: 3x=ln(8)3x=\ln\left(8\right)  

STEP 4: x=ln(83)x=\ln\left(\frac{8}{3}\right)  

5.

MULTIPLE SELECT QUESTION

3 mins • 1 pt

Solve:  3x1=243^{x-1}=24  
Select all possible ways in which you can start solving this equation.

 log(3x1)=log(24)\log\left(3^{x-1}\right)=\log\left(24\right)  

 log3(3x1)=log3(24)\log_3\left(3^{x-1}\right)=\log_3\left(24\right)  

 ln(3x1)=ln(24)\ln\left(3^{x-1}\right)=\ln\left(24\right)  

 3x13=243\frac{3^{x-1}}{3}=\frac{24}{3}  

6.

MULTIPLE SELECT QUESTION

3 mins • 1 pt


 42x=324^{2x}=32  

Select all equations that are equivalent to the equation given above.

 24x=252^{4x}=2^5  

 8x=328^x=32  

 16x=3216^x=32  

 (4)2x=2(4)2\left(4\right)^{2x}=2\cdot\left(4\right)^2  

Tags

CCSS.HSA.CED.A.1

CCSS.HSF.LE.A.2

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

What is the solution of 3e2x+1=53e^{2x}+1=5  ?

 x0.131x\approx0.131  

 x0.187x\approx0.187  

 x0.151x\approx0.151  

 x=0.144x=0.144  

Tags

CCSS.HSF.LE.A.4

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.D.11

CCSS.HSF.BF.B.5

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