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Mathematics

12th Grade

CCSS covered

Used 249+ times

Differential Equations
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8 questions

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1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

2. Solve the differential equation

𝑑𝑦/𝑑𝑡 =3𝑡2/𝑦 with initial condition

𝑦(2) = 0.

y=ln15ty=\ln\left|15t\right|

y=16t3y=16t^3

y = 2t316y\ =\ \sqrt{2t^3-16}

y=2t316y=2t^3-16

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Determine the value of "c" that satisfies the differential equation  dydx=x+1y+2\frac{dy}{dx}=\frac{x+1}{y+2}  if the curve goes through the point (0, -1).

5/2

-3/2

-1/2

1

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Which of the following is the solution to the differential equation  dydx=x2y\frac{dy}{dx}=\frac{x^2}{y}  with the initial condition y(3) = -2?

 y=2e(9+x33)y=-2e^{\left(-9+\frac{x^3}{3}\right)}  

 y=2x33y=\sqrt{\frac{2x^3}{3}}  

 y=2x3314y=\sqrt{\frac{2x^3}{3}-14}  

 y=2x3314y=-\sqrt{\frac{2x^3}{3}-14}  

Tags

CCSS.HSA.SSE.A.1

CCSS.HSN.RN.A.2

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Given the differential equation dP/Dt=5P

A) Find the general solution for P to the differential equation

B)Find the particular solution for P to the differential equation given P(0)= 418

A) P=Ce5t

B) P= 5e418t

A) P=Ce5t

B) P= 418e5t

A) P=Cet

B) P= 418et

A) P=Ce10t

B) P= 418e10t

Tags

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

CCSS.HSF.LE.B.5

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Solve the following differential equations:
 dydx=1cosy\frac{\text{d}y}{\text{d}x}=\frac{1}{\cos y}  

 siny=1+C\sin y=1+C  

 siny=x+C\sin y=x+C  

 siny=x22+C-\sin y=\frac{x^2}{2}+C  

 siny=0+C\sin y=0+C  

Tags

CCSS.HSF.TF.B.7

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Solve the following differential equations:
 dydx=ex\frac{\text{d}y}{\text{d}x}=e^x  

 1=ex+C1=e^x+C  

 y=ex2+Cy=\frac{e^x}{2}+C  

 y=ex+Cy=e^x+C  

 0=ex+C0=e^x+C  

Tags

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

CCSS.HSA.CED.A.1

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Let dydx=0.4y\frac{dy}{dx}=-0.4y and  y=5 y=5\   when  x=0x=0  .  

What is the solution for  yy  ?

 y=5e0.4xy=5e^{-0.4x}  

 y=0.4e5xy=-0.4e^{5x}  

 y=5ex0.4y=5e^{-\frac{x}{0.4}}  

 y=0.4ex5y=0.4e^{\frac{x}{5}}  

Tags

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

CCSS.HSF.LE.B.5

CCSS.HSF.BF.A.1

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