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Jumlah dan selisih 2 sudut

Authored by S.Pd kushendratno

Mathematics

10th Grade

CCSS covered

Used 373+ times

Jumlah dan selisih 2 sudut
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15 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 sin(105°)=...\sin\left(105\degree\right)=...  

 \frac{1}{4}\sqrt{8}  

 12(2+6)\frac{1}{2}\left(\sqrt{2}+\sqrt{6}\right)  

 14(2+6)\frac{1}{4}\left(\sqrt{2}+\sqrt{6}\right)  

 14(26)\frac{1}{4}\left(\sqrt{2}-\sqrt{6}\right)  

 14(62)\frac{1}{4}\left(\sqrt{6}-\sqrt{2}\right)  

Tags

CCSS.HSF.TF.C.9

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 sin(15°)=...\sin\left(15\degree\right)=...  

 \frac{1}{4}\sqrt{8}  

 12(2+6)\frac{1}{2}\left(\sqrt{2}+\sqrt{6}\right)  

 14(2+6)\frac{1}{4}\left(\sqrt{2}+\sqrt{6}\right)  

 14(26)\frac{1}{4}\left(\sqrt{2}-\sqrt{6}\right)  

 14(62)\frac{1}{4}\left(\sqrt{6}-\sqrt{2}\right)  

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 cos(75°)=...\cos\left(75\degree\right)=...  

 \frac{1}{4}\sqrt{8}  

 12(2+6)\frac{1}{2}\left(\sqrt{2}+\sqrt{6}\right)  

 14(2+6)\frac{1}{4}\left(\sqrt{2}+\sqrt{6}\right)  

 14(26)\frac{1}{4}\left(\sqrt{2}-\sqrt{6}\right)  

 14(62)\frac{1}{4}\left(\sqrt{6}-\sqrt{2}\right)  

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 cos85°cos55°+sin85°sin55°=...\cos85\degree\cos55\degree+\sin85\degree\sin55\degree=...  

0

1

 12\frac{1}{2}  

 122\frac{1}{2}\sqrt{2}  

 123\frac{1}{2}\sqrt{3}  

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 sin75°cos15°cos75°sin15°=...\sin75\degree\cos15\degree-\cos75\degree\sin15\degree=...  

0

1

 12\frac{1}{2}  

 122\frac{1}{2}\sqrt{2}  

 123\frac{1}{2}\sqrt{3}  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 sin285°=...\sin285\degree=...  

 14(62)-\frac{1}{4}\left(\sqrt{6}-\sqrt{2}\right)  

 14(6+2)-\frac{1}{4}\left(\sqrt{6}+\sqrt{2}\right)  

 14(6+2)\frac{1}{4}\left(\sqrt{6}+\sqrt{2}\right)  

 14(26)-\frac{1}{4}\left(\sqrt{2}-\sqrt{6}\right)  

 14(62)\frac{1}{4}\left(\sqrt{6}-\sqrt{2}\right)  

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 cos165°=...\cos165\degree=...  

 14(62)-\frac{1}{4}\left(\sqrt{6}-\sqrt{2}\right)  

 14(2+6)-\frac{1}{4}\left(\sqrt{2}+\sqrt{6}\right)  

 14(2+6)\frac{1}{4}\left(\sqrt{2}+\sqrt{6}\right)  

 14(26)-\frac{1}{4}\left(\sqrt{2}-\sqrt{6}\right)  

 14(26)\frac{1}{4}\left(\sqrt{2}-\sqrt{6}\right)  

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