Week 6 Lesson 3 Substitution Method

Solve the system of equations by substitution.
y = -4x + 5
y =  3x - 16

• (-3, -25)
• (3,-7)
• (11, 17)
• (21, 47)

Tags

CCSS.HSA.REI.C.6

CCSS.8.EE.C.8B

What is the solution to the system of equations? 
y = 3x - 8
y = 4 - x

• (3,1)
• (1,3)
• (-3,1)
• (3,-1)

Tags

CCSS.HSA.REI.C.6

CCSS.8.EE.C.8B

This system has _____ solutions

• 0
• 1
• 2
• Infinitely many

Tags

CCSS.8.EE.C.8A

Solve the system of equations below:

y=-3x+10

y=x-14

• (10,-4)

• (2,4)

• (1,-13)

• (6,-8

Solve the following system of equations using substitution:

 $y=\frac{2}{3}x+4$  

 $y=\frac{4}{9}x+1$  

• (9,10)

• (-3,2)

• (0,1)

• (6,8)

solve by substitution: y=3x+14
y=-4x

• y=3
• y=1
• y= - 2
• y=4

Tags

CCSS.HSA.REI.C.6

CCSS.8.EE.C.8B

Solve for x and y (Use Substitution)

y = 2x + 1

y = 4x - 1

• (1,3)

• (-1,-3)

• (-1,3)

• (3,1)

• (1,1)

Tags

CCSS.HSA.REI.C.6

CCSS.8.EE.C.8B

Is the point (2, -1) a solution to the systems of equations below?

y=5x+3

y=-2x-4

• Yes

• No

Tags

CCSS.HSA.REI.C.6

What is the solution?

• (6, 3)
• (3, 6)
• (-6, 3)
• No solution

Tags

CCSS.8.EE.C.8A

What is the solution to the following system of equations?

 $y=-\frac{3}{5}x+8$  

 $y=\frac{1}{2}x-3$  

• (2,-2)

• (0,8)

• (10,2)

• (5,5)