Thể tích vật thể tròn xoay khi hình phẳng giới hạn bởi y = x 3 -1, trục Ox, trục Oy quay quanh Ox là:

9 π 14 \frac{9\pi}{14} 1 4 9 π

14 π 9 \frac{14\pi}{9} 9 1 4 π

Vec tơ nào sau đây là vec tơ pháp tuyến của mặt phẳng (P): x - 2y +3 = 0

n → = ( − 1 ; 2 ; 0 ) \overrightarrow{n}=\left(-1;2;0\right) n <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( − 1 ; 2 ; 0 )

n → = ( − 1 ; 2 ; 3 ) \overrightarrow{n}=\left(-1;2;3\right) n <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( − 1 ; 2 ; 3 )

n → = ( 1 ; − 2 ; 3 ) \overrightarrow{n}=\left(1;-2;3\right) n <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 1 ; − 2 ; 3 )

n → = ( 1 ; 2 ; 0 ) \overrightarrow{n}=\left(1;2;0\right) n <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 1 ; 2 ; 0 )

d : x − 3 = y + 1 2 = z − 2 4 d:\frac{x}{-3}=\frac{y+1}{2}=\frac{z-2}{4} d : − 3 x = 2 y + 1 = 4 z − 2 vec tơ nào dưới đây là vec tơ chỉ phương của đường thẳng

a → = ( 6 ; − 4 ; − 8 ) \overrightarrow{a}=\left(6;-4;-8\right) a <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 6 ; − 4 ; − 8 )

a → = ( 0 ; − 1 ; 2 ) \overrightarrow{a}=\left(0;-1;2\right) a <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 0 ; − 1 ; 2 )

a → = ( 0 ; 1 ; − 2 ) \overrightarrow{a}=\left(0;1;-2\right) a <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 0 ; 1 ; − 2 )

a → = ( 3 ; − 2 ; 4 ) \overrightarrow{a}=\left(3;-2;4\right) a <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = ( 3 ; − 2 ; 4 )

đường thẳng d qua A(1;2;-3) và vuông góc với mặt phẳng (P): x - 2y +z -4=0 có phương trình là:

x = 2 − t ; y = 2 t ; z = − 2 − t x=2-t;\ y=2t;\ z=-2-t x = 2 − t ; y = 2 t ; z = − 2 − t

x + 1 1 = y + 2 − 2 = z − 3 1 \frac{x+1}{1}=\frac{y+2}{-2}=\frac{z-3}{1} 1 x + 1 = − 2 y + 2 = 1 z − 3

x − 1 1 = y − 2 2 = z + 3 1 \frac{x-1}{1}=\frac{y-2}{2}=\frac{z+3}{1} 1 x − 1 = 2 y − 2 = 1 z + 3

x = 1 − t ; y = 2 − 2 t ; z = − 3 + t x=1-t;\ y=2-2t;\ z=-3+t x = 1 − t ; y = 2 − 2 t ; z = − 3 + t

khoảng cách từ A(-1;3;4) đến mặt phẳng (P): x + 3y +z - 1 = 0 bằng

11 \sqrt{11} 1 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

13 11 \frac{13}{\sqrt{11}} 1 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1 3

12 11 \frac{12}{\sqrt{11}} 1 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1 2

11 11 \frac{\sqrt{11}}{11} 1 1 1 1 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

đ ư ờng th ẳng d qua A(-1;2;-3) v à vu ông g óc hai đ ư ờng th ẳng d 1 : x 1 = y − 3 2 = z − 1 d_1:\frac{x}{1}=\frac{y-3}{2}=\frac{z}{-1} d 1 : 1 x = 2 y − 3 = − 1 z d 2 : x + 1 − 2 = y − 2 1 = z 1 d_2:\frac{x+1}{-2}=\frac{y-2}{1}=\frac{z}{1} d 2 : − 2 x + 1 = 1 y − 2 = 1 z c ó ph ư ơng tr ình

x + 1 − 3 = y − 2 − 1 = z + 3 − 5 \frac{x+1}{-3}=\frac{y-2}{-1}=\frac{z+3}{-5} − 3 x + 1 = − 1 y − 2 = − 5 z + 3

x − 1 3 = y + 2 1 = z − 3 5 \frac{x-1}{3}=\frac{y+2}{1}=\frac{z-3}{5} 3 x − 1 = 1 y + 2 = 5 z − 3

x − 3 1 = y − 1 − 2 = z − 5 3 \frac{x-3}{1}=\frac{y-1}{-2}=\frac{z-5}{3} 1 x − 3 = − 2 y − 1 = 3 z − 5

x + 3 − 1 = y + 1 2 = z + 5 − 3 \frac{x+3}{-1}=\frac{y+1}{2}=\frac{z+5}{-3} − 1 x + 3 = 2 y + 1 = − 3 z + 5

Mô đun của z = 2+3i bằng

13 \sqrt{13} 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 \sqrt{5} 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

khoảng cách giữa hai mặt phẳng (P): x- 2y +3z - 6 = 0, (Q):2x - 4 y + 6z +16=0 là:

14 \sqrt{14} 1 4 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

22 14 \frac{22}{\sqrt{14}} 1 4 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 2 2

22 56 \frac{22}{\sqrt{56}} 5 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 2 2

22 \sqrt{22} 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

kiểm tra toán 12

Quiz

•

Mathematics

•

12th Grade

•

Practice Problem

•

Hard

nguyen thao

Used 255+ times

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Diện tích hình phẳng giới hạn bởi y = f(x), trục Ox, x= a, x=b (a<b) được tính bằng công thức

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Thể tích vật thể tròn xoay được sinh ra khi hình phẳng giới hạn bởi y=f(x), trục Ox, x = a, x = b quay quanh Ox được tính bằng công thức

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

, Cho f(x) là hàm số liên tục trên [a;b], F(x) là nguyên hàm của f(x). Chọn khẳng định sai

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Diện tích hình phẳng giới hạn bởi y = x²+2x, trục Ox bằng:

$\frac{4}{3}$

$\frac{2}{3}$

$\frac{1}{3}$

$\frac{5}{3}$

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Thể tích vật thể tròn xoay khi hình phẳng giới hạn bởi y = x³-1, trục Ox, trục Oy quay quanh Ox là:

$\frac{14\pi}{9}$

$\frac{9\pi}{14}$

$\frac{3\pi}{4}$

$\frac{4\pi}{3}$

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Cho $\int_1^3f\left(x\right)dx=3,\ \int_1^2f\left(x\right)dx=5$ . Tính $I=\int_2^3f\left(x\right)dx$

I=2

I=-2

I=8

I=15

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$Cho\ \int_0^1f\left(2x+1\right)dx=4.\ Tính\ I=\int_1^3f\left(x\right)dx$

I=2

I=4

I=8

đáp số khác

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kiểm tra toán 12

20 questions

Diện tích hình phẳng giới hạn bởi y = f(x), trục Ox, x= a, x=b (a<b) được tính bằng công thức

Thể tích vật thể tròn xoay được sinh ra khi hình phẳng giới hạn bởi y=f(x), trục Ox, x = a, x = b quay quanh Ox được tính bằng công thức

, Cho f(x) là hàm số liên tục trên [a;b], F(x) là nguyên hàm của f(x). Chọn khẳng định sai

Diện tích hình phẳng giới hạn bởi y = x²+2x, trục Ox bằng:

Thể tích vật thể tròn xoay khi hình phẳng giới hạn bởi y = x³-1, trục Ox, trục Oy quay quanh Ox là:

Cho $\int_1^3f\left(x\right)dx=3,\ \int_1^2f\left(x\right)dx=5$ . Tính $I=\int_2^3f\left(x\right)dx$

$Cho\ \int_0^1f\left(2x+1\right)dx=4.\ Tính\ I=\int_1^3f\left(x\right)dx$

$Cho\ \int_{-1}^2f\left(x\right)dx=6.\ Tính\ A=\int_0^1f\left(3x-1\right)dx$

$\int_{16}^{55}\frac{1}{x\sqrt{x+9}}dx=a\ln2+b\ln5+c\ln11$
với a, b, c $\in$ Q. Tính $S=a^2+b^2+c^2$

Cho f(x) có đạo hàm trên [1;2], f(2)=2, f(4)=2020. Tính $I=\int_1^2f'\left(2x\right)dx$

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kiểm tra toán 12

20 questions

Diện tích hình phẳng giới hạn bởi y = f(x), trục Ox, x= a, x=b (a<b) được tính bằng công thức

Thể tích vật thể tròn xoay được sinh ra khi hình phẳng giới hạn bởi y=f(x), trục Ox, x = a, x = b quay quanh Ox được tính bằng công thức

, Cho f(x) là hàm số liên tục trên [a;b], F(x) là nguyên hàm của f(x). Chọn khẳng định sai

Diện tích hình phẳng giới hạn bởi y = x2+2x, trục Ox bằng:

Thể tích vật thể tròn xoay khi hình phẳng giới hạn bởi y = x3-1, trục Ox, trục Oy quay quanh Ox là:

Cho ∫13f(x)dx=3, ∫12f(x)dx=5\int_1^3f\left(x\right)dx=3,\ \int_1^2f\left(x\right)dx=5∫13​f(x)dx=3, ∫12​f(x)dx=5 . Tính I=∫23f(x)dxI=\int_2^3f\left(x\right)dxI=∫23​f(x)dx

Cho ∫01f(2x+1)dx=4. Tıˊnh I=∫13f(x)dxCho\ \int_0^1f\left(2x+1\right)dx=4.\ Tính\ I=\int_1^3f\left(x\right)dxCho ∫01​f(2x+1)dx=4. Tıˊnh I=∫13​f(x)dx

Cho ∫−12f(x)dx=6. Tıˊnh A=∫01f(3x−1)dxCho\ \int_{-1}^2f\left(x\right)dx=6.\ Tính\ A=\int_0^1f\left(3x-1\right)dxCho ∫−12​f(x)dx=6. Tıˊnh A=∫01​f(3x−1)dx

∫16551xx+9dx=aln⁡2+bln⁡5+cln⁡11\int_{16}^{55}\frac{1}{x\sqrt{x+9}}dx=a\ln2+b\ln5+c\ln11∫1655​xx+9​1​dx=aln2+bln5+cln11 với a, b, c ∈\in∈ Q. Tính S=a2+b2+c2S=a^2+b^2+c^2S=a2+b2+c2

Cho f(x) có đạo hàm trên [1;2], f(2)=2, f(4)=2020. Tính I=∫12f′(2x)dxI=\int_1^2f'\left(2x\right)dxI=∫12​f′(2x)dx

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Diện tích hình phẳng giới hạn bởi y = x²+2x, trục Ox bằng:

Thể tích vật thể tròn xoay khi hình phẳng giới hạn bởi y = x³-1, trục Ox, trục Oy quay quanh Ox là:

Cho $\int_1^3f\left(x\right)dx=3,\ \int_1^2f\left(x\right)dx=5$ . Tính $I=\int_2^3f\left(x\right)dx$

$Cho\ \int_0^1f\left(2x+1\right)dx=4.\ Tính\ I=\int_1^3f\left(x\right)dx$

$Cho\ \int_{-1}^2f\left(x\right)dx=6.\ Tính\ A=\int_0^1f\left(3x-1\right)dx$

$\int_{16}^{55}\frac{1}{x\sqrt{x+9}}dx=a\ln2+b\ln5+c\ln11$
với a, b, c $\in$ Q. Tính $S=a^2+b^2+c^2$

Cho f(x) có đạo hàm trên [1;2], f(2)=2, f(4)=2020. Tính $I=\int_1^2f'\left(2x\right)dx$