Solving exponential equations

3^2x=1

6^-r = 216

2^-r = 2^3r+1

2^3b * 64 = 2^-3b-3

3^-3x+3 * 81 = 3^x

125³ⁿ*625^-3n=625

 $\frac{16^{2r}}{32}=32^{\left(2r-3\right)}$  

25^-p+1*125^1-3p=25^-p