Alternating Series Test for Convergence

Alternating Series Test for Convergence

11th - 12th Grade

5 Qs

quiz-placeholder

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Alternating Series Test for Convergence

Alternating Series Test for Convergence

Assessment

Quiz

Mathematics

11th - 12th Grade

Practice Problem

Medium

Created by

Araceli Ramirez

Used 36+ times

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5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Determine the convergence or divergence of  n=1(1)n+1n+1\sum_{n=1}^{\infty}\frac{\left(-1\right)^{n+1}}{n+1}  

Converges

Diverges because it does not pass the first condition of AST:  limnan=0\lim_{n\rightarrow\infty}a_n=0  

Diverges because it does not pass the second condition of AST: an+1ana_{n+1}\le a_n  for all n

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Determine the convergence or divergence of  n=1(1)n+1n3n+2\sum_{n=1}^{\infty}\frac{\left(-1\right)^{n+1}n}{3n+2}  

Converges

Diverges because it does not pass the first condition of AST:  limnan=0\lim_{n\rightarrow\infty}a_n=0  

Diverges because it does not pass the second condition of AST: an+1ana_{n+1}\le a_n  for all n

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Determine the convergence or divergence of  n=1(1)nnln(n+1)\sum_{n=1}^{\infty}\frac{\left(-1\right)^nn}{\ln\left(n+1\right)}  

Converges

Diverges because it does not pass the first condition of AST:  limnan=0\lim_{n\rightarrow\infty}a_n=0  

Diverges because it does not pass the second condition of AST: an+1ana_{n+1}\le a_n  for all n

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Determine the convergence or divergence of  n=0(1)nn!\sum_{n=0}^{\infty}\frac{\left(-1\right)^n}{n!}  

Converges

Diverges because it does not pass the first condition of AST:  limnan=0\lim_{n\rightarrow\infty}a_n=0  

Diverges because it does not pass the second condition of AST: an+1ana_{n+1}\le a_n  for all n

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Determine the convergence or divergence of  3222+3323+3424+...\frac{3}{2}-\frac{2}{2}+\frac{3}{3}-\frac{2}{3}+\frac{3}{4}-\frac{2}{4}+...  

Converges

Diverges because it does not pass the first condition of AST:  limnan=0\lim_{n\rightarrow\infty}a_n=0  

Diverges because it does not pass the second condition of AST: an+1ana_{n+1}\le a_n  for all n