Independence Formulas

Events A and B are independent. P(A) = 0.77 P(B) = 0.81. What is the P(AandB)? Round to 2 decimal places.

Tags

CCSS.HSS.CP.A.2

CCSS.HSS.CP.A.4

Knowing how to ride a bike and preferring chocolate are independent events. P(knowing how to ride a bike) = 0.21 and P(preferring chocolate) = 0.37. What is the P(knowing how to ride a bike AND preferring chocolate)? Round to 2 decimal places

Tags

CCSS.HSS.CP.A.2

CCSS.HSS.CP.A.4

Identify whether events A and B are independent based on the following statements.

P(A) = 0.5

P(B) = 0.45

P(AandB) = 0.225

• Yes, because P(A) = P(AandB)

• Yes, because P(A) * P(B) = P(AandB)

• No, because P(A) ≠ P(AandB)

• No, because P(A) * P(B) ≠ P(AandB)

• No, because P(A) ≠ P(A|B)

Tags

CCSS.HSS.CP.A.2

CCSS.HSS.CP.A.4

Identify whether events A and B are independent based on the following statements.

P(A) = 0.2

P(B) = 0.4

P(AandB) = 0.2

• Yes, because P(A) = P(AandB)

• Yes, because P(A) * P(B) = P(AandB)

• No, because P(A) ≠ P(AandB)

• No, because P(A) * P(B) ≠ P(AandB)

• No, because P(A) ≠ P(A|B)

Tags

CCSS.HSS.CP.A.2

CCSS.HSS.CP.A.4

Identify which of the following formulas are ONLY TRUE if events A and B are independent. Select all that apply

• $P\left(A\right)\cdot P\left(B\right)=$
  $P\left(A\cap B\right)$
  

• $P\left(A^c\right)=1-P\left(A\right)$
  

• $P(A|B)=P\left(A\right)$
  

• $P(A|B)=\frac{P\left(A\cap B\right)}{P\left(B\right)}$

Tags

CCSS.HSS.CP.A.3

Being a millionaire and being double jointed are independent events. P(being a millionaire) = 0.08 and P(being double jointed) = 0.30. What is the P(being a millionaire AND being double jointed)? Round to 3 decimal places

Tags

CCSS.HSS.CP.A.2

CCSS.HSS.CP.A.4