FUNCIONES: Dominio, composición, función inversa

FUNCIONES: Dominio, composición, función inversa

10th - 12th Grade

10 Qs

quiz-placeholder

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FUNCIONES: Dominio, composición, función inversa

FUNCIONES: Dominio, composición, función inversa

Assessment

Quiz

Mathematics

10th - 12th Grade

Hard

Created by

Raquel Lorenzo

Used 10+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

El dominio de  f(x)=x+2x3f\left(x\right)=\frac{x+2}{x-3}  es

R-{-2}

R-{3}

R-{-2,3}

 (,2)U(3,)\left(-\infty,-2\right)U\left(3,\infty\right)  

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

El dominio de  f(x)=x+2x2+xf\left(x\right)=\frac{x+2}{x^2+x}  es

R-{0}

(-2,0)U(0,1)

R-{-1,0}

 (,0)U(0,)\left(-\infty,0\right)U\left(0,\infty\right)  

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

El dominio de  f(x)=x1f\left(x\right)=\sqrt{x-1}  es

R-{1}

 [1,)\left[1,\infty\right)  

 (1,)\left(-1,\infty\right)  

 (1,)\left(1,\infty\right)  

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

El dominio de  f(x)=3x21f\left(x\right)=^3\sqrt{x^2-1}  

R-{-1,1}

 [,1)U(1,)\left[-\infty,-1\right)U\left(1,\infty\right)  

 [1,)\left[1,\infty\right)  

R

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

El dominio de  f(x)=x24x+5 f\left(x\right)=\frac{\sqrt{x^2-4}}{x+5}\   es

 (,2)U(2,){5}\left(-\infty,-2\right)U\left(2,\infty\right)-\left\{-5\right\}  

 (,2]U[2,){5}\left(-\infty,-2\right]U\left[2,\infty\right)-\left\{5\right\}  

 (,2]U[2,){5}\left(-\infty,-2\right]U\left[2,\infty\right)-\left\{-5\right\}  

 (,2)U(2,){5}\left(-\infty,-2\right)U\left(2,\infty\right)-\left\{5\right\}  

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Calcula  (f  g)(x)\left(f\ \circ\ g\right)\left(x\right)  

siendo f\left(x\right)=\frac{x+2}{x-1}  y  g(x)=3x+1g\left(x\right)=3x+1  

 3x+2x1+13\frac{x+2}{x-1}+1  

 3x+2x1\frac{3x+2}{x-1}  

 4x+5x1\frac{4x+5}{x-1}  

 x+1x\frac{x+1}{x}  

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Si  f(x)=x+2x1f\left(x\right)=\frac{x+2}{x-1}  y  g(x)=3x+1g\left(x\right)=3x+1  el dominio de  (fg)(x)\left(f\circ g\right)\left(x\right)  es  

R

R-{0}

R-{1}

R-{0,1}

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